Java语言程序设计，填空题

1:ObjectInputStream ,ObjectOutputStream

2:try{}

3:10

4:多继承

5:new

6:int , char

7:KeyListener

8:Applet

以上答案尽请参考

完整代码如下：

public class Complex {

private float real; //实部

private float imagin;//虚部

public Complex(){//无参默认为(0, 2)

thisreal = 0F;

thisimagin = 2F;

}

public String toString(){//以a+bi的形式输出的复数

return real + "+" + imagin + "i";

}

// a+ bi + (c+ di) = (a+c) + (b+d)i

public static Complex add(Complex c1, Complex c2){//两个复数相加

Complex complex = new Complex();

complexsetReal(c1getReal() + c2getReal());

complexsetImagin(c1getImagin() + c2getImagin());

return complex;

}

// a+ bi == c + di----> a==c, b==d --> it's true

public static boolean equal(Complex c1, Complex c2){//比较两个复数是否相等

return c1getReal() == c2getReal() && c1getImagin() == c2getImagin();

}

//a + bi + f = (a+f) + bi

public static Complex addFloat(Complex c1, float fValue){//复数加一浮点数

c1setReal(c1getReal() + fValue);

return c1;

}

public float getImagin() {

return imagin;

}

public void setImagin(float imagin) {

thisimagin = imagin;

}

public float getReal() {

return real;

}

public void setReal(float real) {

thisreal = real;

}

}

public class Point {

int x;

int y;

public Point() {

}

public Point(int x, int y) {

thisx = x;

thisy = y;

}

public Point(int x) {

thisx = x;

thisy = x;

}

public double distance() {//求当前点到原点的距离

return Mathsqrt((x x + y y));

}

public double distance(int x1, int y1) {//求当前点到（x1,y1）的距离

return Mathsqrt((x-x1)(x-x1) + (y-y1) (y-y1));

}

public double distance(Point other){

int x2 = otherx;

int y2 = othery;

return Mathsqrt((x-x2)(x-x2) + (y-y2) (y-y2));

}

}

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