
按照题目要求编写的用javaBean规范设计的学生类Student的Java程序如下
需要创建user.java.test包,把Student.java文件和Test.java文件放入包中,编译Student.java文件并且编译运行Test.java文件得到运行结果
Student.java文件代码如下
package user.java.test
import java.io.Serializable
public class Student implements Serializable{
private static final long serialVersionUID = 1L
private String no
private String name
private double score
public Student(){}
public Student(String no,String name,double score){
this.no=no
this.name=name
this.score=score
}
public String getNo(){ return no}
public void setNo(String no){ this.no=no}
public String getName(){ return name}
public void setName(String name){ this.name=name}
public double getScore(){ return score}
public void setScore(double score){ this.score=score}
public String toString(){
return "学号:"+no+",姓名:"+name+",成绩:"+score
}
public static double getAvg(Student[] sArray){
double sum=0,avg
for(int i=0i<sArray.lengthi++){
sum=sum+sArray[i].getScore()
}
avg=sum/sArray.length
return avg
}
}
Test.java文件代码如下
package user.java.test
public class Test{
public static void main(String[] args){
Student[] sArray=new Student[5]
sArray[0]=new Student("001","张三",89.5)
sArray[1]=new Student("002","李四",82.5)
sArray[2]=new Student("003","王五",93)
sArray[3]=new Student("004","赵六",73.5)
sArray[4]=new Student("005","孙七",66)
System.out.println("这些学生的平均分:"+Student.getAvg(sArray))
for(int i=0i<sArray.lengthi++){
System.out.println(sArray[i].toString())
}
}
}
没那么多时间,帮着写个第1题吧
// 编写求一个整数数组A[10,15,12,9,7]中最小元素min和元素之和sum的
int [] a = {10,15,15,9,7}
// 最小元素
int min=0
// 数组和
int sum=0
for(int i=0 i<a.length i++ ){
sum += a[i]
if(i == 0){
min = a[i]
}else{
if(a[i] < min){
min = a[i]
}
}
}
System.out.println("当前数组中最小的元素值是: "+min)
System.out.println("当前数组和是: "+sum)
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