
NSData *data = [NSData dataWithContentsOffile:filePath];NSLog(@"file Size: %i",[data length]);//set up requestNSMutableURLRequest *request= [[NSMutableURLRequest alloc] init];[request setURL:[NSURL URLWithString:urlString]];[request sethttpMethod:@"POST"];//required xtra infoNsstring *boundary = @"---------------------------14737809831466499882746641449";Nsstring *ContentType = [Nsstring stringWithFormat:@"multipart/form-data; boundary=%@",boundary];[request addValue:ContentType forhttpheaderFIEld: @"Content-Type"];//body of the postNSMutableData *postbody = [NSMutableData data];[postbody appendData:[[Nsstring stringWithFormat:@"\r\n--%@--\r\n",boundary] dataUsingEnCoding:NSUTF8StringEnCoding]];[postbody appendData:[[Nsstring stringWithFormat:@"Content-disposition: form-data; name=\"thefile\"; filename=\"recording\"\r\n"] dataUsingEnCoding:NSUTF8StringEnCoding]];[postbody appendData:[[Nsstring stringWithString:@"Content-Type: application/octet-stream\r\n"] dataUsingEnCoding:NSUTF8StringEnCoding]];[postbody appendData:data];[postbody appendData:[[Nsstring stringWithFormat:@"\r\n--%@--\r\n",boundary] dataUsingEnCoding:NSUTF8StringEnCoding]];[request sethttpBody:postbody];APIConnection = [[NSURLConnection alloc] initWithRequest:request delegate:self];
这是PHP代码:
if (is_uploaded_file($_fileS['thefile']['tmp_name'])) { echo "file name: ".$_fileS['thefile']['name'];} else { echo "nothing";} 文件大小取决于录制的音频长度,但有数据.
我得到了“没什么”的回应.
解决方法 要调试:在PHP端,尝试:$file = $_POST['name'];echo $file
尝试使用以下代码段代替当前代码.将URL(www.yourWebAddress.com)和脚本名称更改为适合您问题的值.
NSData *data = [NSData dataWithContentsOffile:filePath];NSMutableString *urlString = [[NSMutableString alloc] initWithFormat:@"name=thefile&&filename=recording"];[urlString appendFormat:@"%@",data];NSData *postData = [urlString dataUsingEnCoding:NSASCIIStringEnCoding allowLossyConversion:YES];Nsstring *postLength = [Nsstring stringWithFormat:@"%d",[postData length]];Nsstring *baseurl = @"https://www.yourWebAddress.com/yourServerScript.PHP"; NSURL *url = [NSURL URLWithString:baseurl];NSMutableURLRequest *urlRequest = [NSMutableURLRequest requestWithURL:url];[urlRequest sethttpMethod: @"POST"];[urlRequest setValue:postLength forhttpheaderFIEld:@"Content-Length"];[urlRequest setValue:@"application/x-www-form-urlencoded" forhttpheaderFIEld:@"Content-Type"];[urlRequest sethttpBody:postData];NSURLConnection *connection = [NSURLConnection connectionWithRequest:urlRequest delegate:self];[connection start];NSLog(@"Started!");
在服务器端,我有以下代码:
<?PHP $name = $_POST['name']; $filename = $_POST['filename']; echo "name = '" . $name . "',filename = '" . $filename . "'."; error_log ( "name = '" . $name . "',filename = '" . $filename . "'." );?>
我收到了以下输出:
[23-May-2012 11:56:18] name =’thefile’,filename =’recording’.
我不知道为什么它不适合你.你必须缺少一步.尝试在上面引用“数据”的url POST代码中注释掉两行,以确保您至少可以获得服务器端的名称和文件名的纯文本.
祝你好运!
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