
'放四个text1-text4,四个label1-label4,一个command1,调整好大小和位置
'代码如下:
private sub form_load()
label1caption ="本金"
label2caption="存款年数"
label3caption="年利率"
label4caption="到期利息"
endsub
private sub command1_click()
dim a as single
dim n as integer
dim p as single
dim Lx as single
a=val(text1text)
n=val(text2text)
p=val(text3text)
Lx=a(1+p)^n-a
text4text=Lx
end sub
有什么疑问请留言。
简单些了个,如果没理解错的话,应该可以满足要求:
public class Benxi{
private double benxi;//本息
private double lilu;//年利率
//计算本息
private double resBenxi(double money,int year){
benxi=money+moneygetLilu(year)year;
return benxi;
}
//选择利率
private double getLilu(int year){
switch(year){
case 1:
lilu=225/100;
break;
case 2:
lilu=27/100;
break;
case 3:
lilu=324/100;
break;
case 5:
lilu=36/100;
break;
}
return lilu;
}
public static void main(String[] args){
Benxi bx=new Benxi();
Systemoutprintln("10000元存一年的本息为:"+bxresBenxi(10000,1));
Systemoutprintln("10000元存两年的本息为:"+bxresBenxi(10000,2));
Systemoutprintln("10000元存三年的本息为:"+bxresBenxi(10000,3));
Systemoutprintln("10000元存五年的本息为:"+bxresBenxi(10000,5));
}
}
Private Sub HScroll1_Change()
HScroll1Max = 12
HScroll1Min = 1
HScroll1LargeChange = 1
Text2Text = CStr(HScroll1Value)
ChgResult
End Sub
Private Sub HScroll2_Change()
HScroll2Max = 150
HScroll2Min = 0
Text3Text = CStr(HScroll2Value)
ChgResult
End Sub
Private Sub VScroll1_Change()
Text1Text = CStr(VScroll1Value)
ChgResult
End Sub
Sub ChgResult()
Text4Text = CStr(Val(Text1Text) Val(Text3Text) / 100 Val(Text2Text) / 12)
Text5 = CStr(Val(Text4) + Val(Text1))
End Sub
#include<iostream>
#include<fstream>
using namespace std;
class savingsaccount
{
public:
float Annual; //(年利率)
float calculate();
float modify(float a);
float smodify(float a);
float save();
private:
float savings; //表示当前存款额
};
float savingsaccount::calculate()
{
float month;
month=(savingsAnnual)/12;
savings+=month;
return savings;
}
float savingsaccount::modify(float a)
{
Annual=a;
return Annual;
}
float savingsaccount::smodify(float a)
{
savings =a;
return a;
}
float savingsaccount::save()
{
return savings;
}
void main()
{
int i;
savingsaccount save1,save2;
save1smodify(120000);
save1modify(003);
save2smodify(300000);
save2modify(003);
for(i=1;i<=12;i++)
{
save1calculate();
cout<<i<<"月份"<<save1save()<<endl;
}
cout<<endl;
for(i=1;i<=12;i++)
{
save2calculate();
cout<<i<<"月份"<<save2save()<<endl;
}
}
using System;
namespace TestCSharp
{
class Program
{
static void Main(string[] args)
{
ConsoleWriteLine("请输入存款额:");
string strDeposit = ConsoleReadLine();
ConsoleWriteLine("请输入年利率:");
string strRate = ConsoleReadLine();
double deposit = 0;
double rate = 0;
try
{
deposit = doubleParse(strDeposit);
rate = doubleParse(strRate);
}
catch
{
ConsoleWriteLine("存款额和年利率必须为数字");
ConsoleReadKey();
return;
}
double sum = (1+rate)deposit;
ConsoleWriteLine("一年后本息总额为:" + sumToString());
ConsoleReadKey();
}
}
}
#include <stdioh>
void main()
{int money,year;
float rate,interest;
printf("input money:\n");
scanf("%d",&money);
printf("input rate:\n");
scanf("%f",&rate);
printf("input year:\n");
scanf("%d",&year);
interest=money(1+rate)year-money;
printf("the interest is:%2f\n",interest);
}
有问题再找我
public class Test {
public static void main(String[] args) {
double rate = 30 / 100; // 利息3%
double amt = 10000; // 金额 10000
int daysOfYear = 365; // 利息计算方式
int term = 365; // 存多久 365天表示一年
// 利息
double interest = (term / daysOfYear) (amt rate);
// 到期金额
double mamt = interest + amt;
Systemoutprintln(amt + "元存银行" + term + "天,利息是:" + interest + ",到期金额是:" + mamt + "。");
}
}
以上就是关于vb电脑编程 编写一个程序,根据本金a、存款年数n和年利率p计算到期利息。提示:到期利息计全部的内容,包括:vb电脑编程 编写一个程序,根据本金a、存款年数n和年利率p计算到期利息。提示:到期利息计、用java编写程序:求银行本息的!题目如下:、VB编写利息计算程序。当通过滚动条改变本金 月份或年利率时,能立即计算出利息及本息合计的值等相关内容解答,如果想了解更多相关内容,可以关注我们,你们的支持是我们更新的动力!
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