
#include "reg51h"
#define data_point P0
sbit EOC=P2^0;
sbit ADDA=P2^1;
sbit ADDB=P2^2;
sbit ADDC=P2^3;
sbit OE=P2^5;
sbit START=P2^6;
sbit CLK=P2^7;
sbit ALE=P2^6;
unsigned char disp[3]={0,0,0};
char code dispcode[]={0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,0x80,0x90};
unsigned char t0count=0;
unsigned int temp;
double sum;
unsigned char val_Integer; //整数
unsigned int val_Decimal; //小数
sbit k1 = P1^0;
sbit k2 = P1^1;
sbit k3 = P1^2;
sbit k4 = P1^3;
void delay(unsigned char ms)
{
unsigned char i;
while(ms--)
for(i=0;i<125;i++);
}
void display()
{
disp[0]=disp[0]&0x7f;
P3= disp[0];
k1 = 1;
delay(2);
k1 = 0;
P3= disp[1];
k2 = 1;
delay(2);
k2 = 0;
P3= disp[2];
k3 = 1;
delay(2);
k3 = 0;
P3= disp[3];
k4 = 1;
delay(2);
k4 = 0;
}
unsigned char ADC0808()
{
unsigned char d;
ADDC=0;
ADDB=0;
ADDA=0;
TR1=1;
ALE=1;ALE=0;
START=1;START=0;
while(EOC==0);
OE=1;
d=data_point;
OE=0;
TR1=1;
return d;
}
void covert(unsigned char x)
{
sum=x00201378;
val_Integer=(unsigned char)sum;
val_Decimal=(unsigned int)((sum-val_Integer)1000);
disp[3]=dispcode[val_Decimal%10];
disp[2]=dispcode[val_Decimal/10%10];
disp[1]=dispcode[val_Decimal/100];
disp[0]=dispcode[val_Integer];
}
void main()
{
TMOD=0x21;
TH0=(65536-10000)/256;
TL0=(65536-10000)%256;
TH1=256-2;
ET0=1;
ET1=1;
EA=1;
TR0=1;
OE=0;
START=0;
EOC=1;
while(1)
{
display();
}
}
void time0() interrupt 1
{
TH0=(65536-10000)/256;
TL0=(65536-10000)%256;
t0count++;
if(t0count==100)
{
t0count=0;
covert(ADC0808());
}
}
void time1() interrupt 3
{
CLK=~CLK;
}
兄弟:不知道你玩不玩32 ,有个32 的在工程上用过,直接刷程序,串口连接电脑就可以输出AD 转换的结果。如果不玩32 的话。
首先第一步排查: 排查单片机能不能正确显示 你测试到的 AD 信号,显示正确不?
比如给他 3V 电压 ,用数码管显示出来。
第二: 串口发送,找个能正确发送数据的代码 ,直接把 ,你检查的数值给这个变量,让串口发送,
一步一步找问题,你绝对能解决的。我把AD0809 的代码给你用数码管测试
#include <reg52h>
#define uint unsigned int
#define uchar unsigned char
uchar code LEDData[]=
{
0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f
};
sbit OE = P1^0;
sbit EOC = P1^1;
sbit ST = P1^2;
sbit CLK = P1^3;
void DelayMS(uint ms)
{
uchar i;
while(ms--)
{
for(i=0;i<120;i++);
}
}
void Display_Result(uchar d)
{
P2 = 0xf7;
P0 = LEDData[d%10];
DelayMS(5);
P2 = 0xfb;
P0 = LEDData[d%100/10];
DelayMS(5);
P2 = 0xfd;
P0 = LEDData[d/100];
DelayMS(5);
}
void main()
{
TMOD = 0x02;
TH0 = 0x14;
TL0 = 0x00;
IE = 0x82;
TR0 = 1;
P1 = 0x3f;
while(1)
{
ST = 0;
ST = 1;
ST = 0;
while(EOC == 0);
OE = 1;
Display_Result(P3);
OE = 0;
}
}
void Timer0_INT() interrupt 1
{
CLK = !CLK;
}
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