des加密算法都是一样的，可能是你的加密密钥不一样，net里面使用加密服务，你可以使用DESCreate创建加密类，具体使用方法请你参考msdn
至于vb6应该有相应的模块可以用，不过我不熟悉这一块
一．加密
DES算法处理的数据对象是一组64比特的明文串。设该明文串为m=m1m2…m64 (mi=0或1)。明文串经过64比特的密钥K来加密，最后生成长度为64比特的密文E。其加密过程图示如下：
DES算法加密过程
对DES算法加密过程图示的说明如下：待加密的64比特明文串m，经过IP置换后，得到的比特串的下标列表如下：
IP 58 50 42 34 26 18 10 2
60 52 44 36 28 20 12 4
62 54 46 38 30 22 14 6
64 56 48 40 32 24 16 8
57 49 41 33 25 17 9 1
59 51 43 35 27 19 11 3
61 53 45 37 29 21 13 5
63 55 47 39 31 23 15 7
该比特串被分为32位的L0和32位的R0两部分。R0子密钥K1(子密钥的生成将在后面讲)经过变换f(R0,K1)（f变换将在下面讲）输出32位的比特串f1,f1与L0做不进位的二进制加法运算。运算规则为：
f1与L0做不进位的二进制加法运算后的结果赋给R1，R0则原封不动的赋给L1。L1与R0又做与以上完全相同的运算，生成L2，R2…… 一共经过16次运算。最后生成R16和L16。其中R16为L15与f(R15,K16)做不进位二进制加法运算的结果，L16是R15的直接赋值。
R16与L16合并成64位的比特串。值得注意的是R16一定要排在L16前面。R16与L16合并后成的比特串，经过置换IP-1后所得比特串的下标列表如下：
IP-1 40 8 48 16 56 24 64 32
39 7 47 15 55 23 63 31
38 6 46 14 54 22 62 30
37 5 45 13 53 21 61 29
36 4 44 12 52 20 60 28
35 3 43 11 51 19 59 27
34 2 42 10 50 18 58 26
33 1 41 9 49 17 57 25
经过置换IP-1后生成的比特串就是密文e。
下面再讲一下变换f(Ri-1,Ki)。
它的功能是将32比特的输入再转化为32比特的输出。其过程如图所示：
对f变换说明如下：输入Ri-1(32比特)经过变换E后，膨胀为48比特。膨胀后的比特串的下标列表如下：
E: 32 1 2 3 4 5
4 5 6 7 8 9
8 9 10 11 12 13
12 13 14 15 16 17
16 17 18 19 20 21
20 21 22 23 24 25
24 25 26 27 28 29
28 29 30 31 32 31
膨胀后的比特串分为8组，每组6比特。各组经过各自的S盒后，又变为4比特(具体过程见后)，合并后又成为32比特。该32比特经过P变换后，其下标列表如下：
P: 16 7 20 21
29 12 28 17
1 15 23 26
5 18 31 10
2 8 24 14
32 27 3 9
19 13 30 6
22 11 4 25
经过P变换后输出的比特串才是32比特的f (Ri-1,Ki)。
下面再讲一下S盒的变换过程。任取一S盒。见图：
在其输入b1,b2,b3,b4,b5,b6中，计算出x=b12+b6, y=b5+b42+b34+b28，再从Si表中查出x 行，y 列的值Sxy。将Sxy化为二进制，即得Si盒的输出。（S表如图所示）
至此，DES算法加密原理讲完了。在VC++60下的程序源代码为：
for(i=1;i<=64;i++)
m1[i]=m[ip[i-1]];//64位明文串输入，经过IP置换。
下面进行迭代。由于各次迭代的方法相同只是输入输出不同，因此只给出其中一次。以第八次为例：//进行第八次迭代。首先进行S盒的运算，输入32位比特串。
for(i=1;i<=48;i++)//经过E变换扩充，由32位变为48位
RE1[i]=R7[E[i-1]];
for(i=1;i<=48;i++)//与K8按位作不进位加法运算
RE1[i]=RE1[i]+K8[i];
for(i=1;i<=48;i++)
{
if(RE1[i]==2)
RE1[i]=0;
}
for(i=1;i<7;i++)//48位分成8组
{
s11[i]=RE1[i];
s21[i]=RE1[i+6];
s31[i]=RE1[i+12];
s41[i]=RE1[i+18];
s51[i]=RE1[i+24];
s61[i]=RE1[i+30];
s71[i]=RE1[i+36];
s81[i]=RE1[i+42];
}//下面经过S盒，得到8个数。S1,s2,s3,s4,s5,s6,s7,s8分别为S表
s[1]=s1[s11[6]+s11[1]2][s11[5]+s11[4]2+s11[3]4+s11[2]8];
s[2]=s2[s21[6]+s21[1]2][s21[5]+s21[4]2+s21[3]4+s21[2]8];
s[3]=s3[s31[6]+s31[1]2][s31[5]+s31[4]2+s31[3]4+s31[2]8];
s[4]=s4[s41[6]+s41[1]2][s41[5]+s41[4]2+s41[3]4+s41[2]8];
s[5]=s5[s51[6]+s51[1]2][s51[5]+s51[4]2+s51[3]4+s51[2]8];
s[6]=s6[s61[6]+s61[1]2][s61[5]+s61[4]2+s61[3]4+s61[2]8];
s[7]=s7[s71[6]+s71[1]2][s71[5]+s71[4]2+s71[3]4+s71[2]8];
s[8]=s8[s81[6]+s81[1]2][s81[5]+s81[4]2+s81[3]4+s81[2]8];
for(i=0;i<8;i++)//8个数变换输出二进制
{
for(j=1;j<5;j++)
{
temp[j]=s[i+1]%2;
s[i+1]=s[i+1]/2;
}
for(j=1;j<5;j++)
f[4i+j]=temp[5-j];
}
for(i=1;i<33;i++)//经过P变换
frk[i]=f[P[i-1]];//S盒运算完成
for(i=1;i<33;i++)//左右交换
L8[i]=R7[i];
for(i=1;i<33;i++)//R8为L7与f(R,K)进行不进位二进制加法运算结果
{
R8[i]=L7[i]+frk[i];
if(R8[i]==2)
R8[i]=0;
}
[ 原创文档 本文适合中级读者 已阅读21783次 ] 文档 代码 工具
DES算法及其在VC++60下的实现(下)
作者：航天医学工程研究所四室 朱彦军
在《DES算法及其在VC++60下的实现(上)》中主要介绍了DES算法的基本原理，下面让我们继续：
二．子密钥的生成
64比特的密钥生成16个48比特的子密钥。其生成过程见图：
子密钥生成过程具体解释如下：
64比特的密钥K，经过PC-1后，生成56比特的串。其下标如表所示：
PC-1 57 49 41 33 25 17 9
1 58 50 42 34 26 18
10 2 59 51 43 35 27
19 11 3 60 52 44 36
63 55 47 39 31 23 15
7 62 54 46 38 30 22
14 6 61 53 45 37 29
21 13 5 28 20 12 4
该比特串分为长度相等的比特串C0和D0。然后C0和D0分别循环左移1位，得到C1和D1。C1和D1合并起来生成C1D1。C1D1经过PC-2变换后即生成48比特的K1。K1的下标列表为：
PC-2 14 17 11 24 1 5
3 28 15 6 21 10
23 19 12 4 26 8
16 7 27 20 13 2
41 52 31 37 47 55
30 40 51 45 33 48
44 49 39 56 34 53
46 42 50 36 29 32
C1、D1分别循环左移LS2位，再合并，经过PC-2，生成子密钥K2……依次类推直至生成子密钥K16。
注意：Lsi (I =1,2,…16)的数值是不同的。具体见下表：
迭代顺序 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16
左移位数 1 1 2 2 2 2 2 2 1 2 2 2 2 2 2 1
生成子密钥的VC程序源代码如下：
for(i=1;i<57;i++)//输入64位K，经过PC-1变为56位 k0[i]=k[PC_1[i-1]];
56位的K0，均分为28位的C0，D0。C0，D0生成K1和C1，D1。以下几次迭代方法相同，仅以生成K8为例。 for(i=1;i<27;i++)//循环左移两位
{
C8[i]=C7[i+2];
D8[i]=D7[i+2];
}
C8[27]=C7[1];
D8[27]=D7[1];
C8[28]=C7[2];
D8[28]=D7[2];
for(i=1;i<=28;i++)
{
C[i]=C8[i];
C[i+28]=D8[i];
}
for(i=1;i<=48;i++)
K8[i]=C[PC_2[i-1]];//生成子密钥k8
注意：生成的子密钥不同，所需循环左移的位数也不同。源程序中以生成子密钥 K8为例，所以循环左移了两位。但在编程中，生成不同的子密钥应以Lsi表为准。
三．解密
DES的解密过程和DES的加密过程完全类似，只不过将16圈的子密钥序列K1，K2……K16的顺序倒过来。即第一圈用第16个子密钥K16，第二圈用K15，其余类推。
第一圈：
加密后的结果
L=R15, R=L15⊕f(R15,K16)⊕f(R15,K16)=L15
同理R15=L14⊕f(R14,K15), L15=R14。
同理类推：
得 L=R0, R=L0。
其程序源代码与加密相同。在此就不重写。
四．示例
例如：已知明文m=learning, 密钥 k=computer。
明文m的ASCII二进制表示：
m= 01101100 01100101 01100001 01110010
01101110 01101001 01101110 01100111
密钥k的ASCII二进制表示：
k=01100011 01101111 01101101 01110000
01110101 01110100 01100101 01110010
明文m经过IP置换后，得：
11111111 00001000 11010011 10100110 00000000 11111111 01110001 11011000
等分为左右两段：
L0=11111111 00001000 11010011 10100110 R0=00000000 11111111 01110001 11011000
经过16次迭代后，所得结果为：
L1=00000000 11111111 01110001 11011000 R1=00110101 00110001 00111011 10100101
L2=00110101 00110001 00111011 10100101 R2=00010111 11100010 10111010 10000111
L3=00010111 11100010 10111010 10000111 R3=00111110 10110001 00001011 10000100
L4=00111110101100010000101110000100 R4=11110111110101111111101000111110
L5=11110111110101111111101000111110 R5=10010110011001110100111111100101
L6=10010110011001110100111111100101 R6=11001011001010000101110110100111
L7=11001011001010000101110110100111 R7=01100011110011101000111011011001
L8=01100011110011101000111011011001 R8=01001011110100001111001000000100
L9=01001011110100001111001000000100 R9=00011101001101111010111011100001
L10=00011101001101111010111011100001 R10=11101110111110111111010100000101
L11=11101110111110111111010100000101 R11=01101101111011011110010111111000
L12=01101101111011011110010111111000 R12=11111101110011100111000110110111
L13=11111101110011100111000110110111 R13=11100111111001011010101000000100
L14=11100111111001011010101000000100 R14=00011110010010011011100001100001
L15=00011110010010011011100001100001 R15=01010000111001001101110110100011
L16=01010000111001001101110110100011 R16=01111101101010000100110001100001
其中，f函数的结果为：
f1=11001010001110011110100000000011 f2=00010111000111011100101101011111
f3=00001011100000000011000000100001 f4=11100000001101010100000010111001
f5=10101000110101100100010001100001 f6=00111100111111111010011110011001
f7=11110101101010011100000100111100 f8=10000000111110001010111110100011
f9=01111110111110010010000000111000 f10=10100101001010110000011100000001
f11=01110000110110100100101100011001 f12=00010011001101011000010010110010
f13=10001010000010000100111111111100 f14=11100011100001111100100111010110
f15=10110111000000010111011110100111 f16=01100011111000011111010000000000
16个子密钥为：
K1=11110000101111101110111011010000 K2=11100000101111101111011010010101
K3=11110100111111100111011000101000 K4=11100110111101110111001000011010
K5=11101110110101110111011100100110 K6=11101111110100110101101110001011
K7=00101111110100111111101111100110 K8=10111111010110011101101101010000
K9=00011111010110111101101101000100 K10=00111111011110011101110100001001
K11=00011111011011011100110101101000 K12=01011011011011011011110100001010
K13=11011101101011011010110110001111 K14=11010011101011101010111110000000
K15=11111001101111101010011011010011 K16=11110001101111100010111000000001
S盒中，16次运算时，每次的8 个结果为：
第一次：5，11，4，1，0，3，13，9；
第二次：7，13，15，8，12，12，13，1；
第三次：8，0，0，4，8，1，9，12；
第四次：0，7，4，1，7，6，12，4；
第五次：8，1，0，11，5，0，14，14；
第六次：14，12，13，2，7，15，14，10；
第七次：12，15，15，1，9，14，0，4；
第八次：15，8，8，3，2，3，14，5；
第九次：8，14，5，2，1，15，5，12；
第十次：2，8，13，1，9，2，10，2；
第十一次：10，15，8，2，1，12，12，3；
第十二次：5，4，4，0，14，10，7，4；
第十三次：2，13，10，9，2，4，3，13；
第十四次：13，7，14，9，15，0，1，3；
第十五次：3，1，15，5，11，9，11，4；
第十六次：12，3，4，6，9，3，3，0；
子密钥生成过程中，生成的数值为：
C0=0000000011111111111111111011 D0=1000001101110110000001101000
C1=0000000111111111111111110110 D1=0000011011101100000011010001
C2=0000001111111111111111101100 D2=0000110111011000000110100010
C3=0000111111111111111110110000 D3=0011011101100000011010001000
C4=0011111111111111111011000000 D4=1101110110000001101000100000
C5=1111111111111111101100000000 D5=0111011000000110100010000011
C6=1111111111111110110000000011 D6=1101100000011010001000001101
C7=1111111111111011000000001111 D7=0110000001101000100000110111
C8=1111111111101100000000111111 D8=1000000110100010000011011101
C9=1111111111011000000001111111 D9=0000001101000100000110111011
C10=1111111101100000000111111111 D10=0000110100010000011011101100
C11=1111110110000000011111111111 D11=0011010001000001101110110000
C12=1111011000000001111111111111 D12=1101000100000110111011000000
C13=1101100000000111111111111111 D13=0100010000011011101100000011
C14=0110000000011111111111111111 D14=0001000001101110110000001101
C15=1000000001111111111111111101 D15=0100000110111011000000110100
C16=0000000011111111111111111011 D16=1000001101110110000001101000
desh文件：
#ifndef CRYPTOPP_DES_H
#define CRYPTOPP_DES_H
#include "cryptlibh"
#include "misch"
NAMESPACE_BEGIN(CryptoPP)
class DES : public BlockTransformation
{
public:
DES(const byte userKey, CipherDir);
void ProcessBlock(const byte inBlock, byte outBlock) const;
void ProcessBlock(byte inoutBlock) const
{DES::ProcessBlock(inoutBlock, inoutBlock);}
enum {KEYLENGTH=8, BLOCKSIZE=8};
unsigned int BlockSize() const {return BLOCKSIZE;}
protected:
static const word32 Spbox[8][64];
SecBlock<word32> k;
};
class DESEncryption : public DES
{
public:
DESEncryption(const byte userKey)
: DES (userKey, ENCRYPTION) {}
};
class DESDecryption : public DES
{
public:
DESDecryption(const byte userKey)
: DES (userKey, DECRYPTION) {}
};
class DES_EDE_Encryption : public BlockTransformation
{
public:
DES_EDE_Encryption(const byte userKey)
: e(userKey, ENCRYPTION), d(userKey + DES::KEYLENGTH, DECRYPTION) {}
void ProcessBlock(const byte inBlock, byte outBlock) const;
void ProcessBlock(byte inoutBlock) const;
enum {KEYLENGTH=16, BLOCKSIZE=8};
unsigned int BlockSize() const {return BLOCKSIZE;}
private:
DES e, d;
};
class DES_EDE_Decryption : public BlockTransformation
{
public:
DES_EDE_Decryption(const byte userKey)
: d(userKey, DECRYPTION), e(userKey + DES::KEYLENGTH, ENCRYPTION) {}
void ProcessBlock(const byte inBlock, byte outBlock) const;
void ProcessBlock(byte inoutBlock) const;
enum {KEYLENGTH=16, BLOCKSIZE=8};
unsigned int BlockSize() const {return BLOCKSIZE;}
private:
DES d, e;
};
class TripleDES_Encryption : public BlockTransformation
{
public:
TripleDES_Encryption(const byte userKey)
: e1(userKey, ENCRYPTION), d(userKey + DES::KEYLENGTH, DECRYPTION),
e2(userKey + 2DES::KEYLENGTH, ENCRYPTION) {}
void ProcessBlock(const byte inBlock, byte outBlock) const;
void ProcessBlock(byte inoutBlock) const;
enum {KEYLENGTH=24, BLOCKSIZE=8};
unsigned int BlockSize() const {return BLOCKSIZE;}
private:
DES e1, d, e2;
};
class TripleDES_Decryption : public BlockTransformation
{
public:
TripleDES_Decryption(const byte userKey)
: d1(userKey + 2DES::KEYLENGTH, DECRYPTION), e(userKey + DES::KEYLENGTH, ENCRYPTION),
d2(userKey, DECRYPTION) {}
void ProcessBlock(const byte inBlock, byte outBlock) const;
void ProcessBlock(byte inoutBlock) const;
enum {KEYLENGTH=24, BLOCKSIZE=8};
unsigned int BlockSize() const {return BLOCKSIZE;}
private:
DES d1, e, d2;
};
NAMESPACE_END
#endif
descpp文件：
// descpp - modified by Wei Dai from:
/
This is a major rewrite of my old public domain DES code written
circa 1987, which in turn borrowed heavily from Jim Gillogly's 1977
public domain code I pretty much kept my key scheduling code, but
the actual encrypt/decrypt routines are taken from from Richard
Outerbridge's DES code as printed in Schneier's "Applied Cryptography"
This code is in the public domain I would appreciate bug reports and
enhancements
Phil Karn KA9Q, karn@unixka9qamprorg, August 1994
/
#include "pchh"
#include "misch"
#include "desh"
NAMESPACE_BEGIN(CryptoPP)
/ Tables defined in the Data Encryption Standard documents
Three of these tables, the initial permutation, the final
permutation and the expansion operator, are regular enough that
for speed, we hard-code them They're here for reference only
Also, the S and P boxes are used by a separate program, genspc,
to build the combined SP box, Spbox[] They're also here just
for reference
/
#ifdef notdef
/ initial permutation IP /
static byte ip[] = {
58, 50, 42, 34, 26, 18, 10, 2,
60, 52, 44, 36, 28, 20, 12, 4,
62, 54, 46, 38, 30, 22, 14, 6,
64, 56, 48, 40, 32, 24, 16, 8,
57, 49, 41, 33, 25, 17, 9, 1,
59, 51, 43, 35, 27, 19, 11, 3,
61, 53, 45, 37, 29, 21, 13, 5,
63, 55, 47, 39, 31, 23, 15, 7
};
/ final permutation IP^-1 /
static byte fp[] = {
40, 8, 48, 16, 56, 24, 64, 32,
39, 7, 47, 15, 55, 23, 63, 31,
38, 6, 46, 14, 54, 22, 62, 30,
37, 5, 45, 13, 53, 21, 61, 29,
36, 4, 44, 12, 52, 20, 60, 28,
35, 3, 43, 11, 51, 19, 59, 27,
34, 2, 42, 10, 50, 18, 58, 26,
33, 1, 41, 9, 49, 17, 57, 25
};
/ expansion operation matrix /
static byte ei[] = {
32, 1, 2, 3, 4, 5,
4, 5, 6, 7, 8, 9,
8, 9, 10, 11, 12, 13,
12, 13, 14, 15, 16, 17,
16, 17, 18, 19, 20, 21,
20, 21, 22, 23, 24, 25,
24, 25, 26, 27, 28, 29,
28, 29, 30, 31, 32, 1
};
/ The (in)famous S-boxes /
static byte sbox[8][64] = {
/ S1 /
14, 4, 13, 1, 2, 15, 11, 8, 3, 10, 6, 12, 5, 9, 0, 7,
0, 15, 7, 4, 14, 2, 13, 1, 10, 6, 12, 11, 9, 5, 3, 8,
4, 1, 14, 8, 13, 6, 2, 11, 15, 12, 9, 7, 3, 10, 5, 0,
15, 12, 8, 2, 4, 9, 1, 7, 5, 11, 3, 14, 10, 0, 6, 13,
/ S2 /
15, 1, 8, 14, 6, 11, 3, 4, 9, 7, 2, 13, 12, 0, 5, 10,
3, 13, 4, 7, 15, 2, 8, 14, 12, 0, 1, 10, 6, 9, 11, 5,
0, 14, 7, 11, 10, 4, 13, 1, 5, 8, 12, 6, 9, 3, 2, 15,
13, 8, 10, 1, 3, 15, 4, 2, 11, 6, 7, 12, 0, 5, 14, 9,
/ S3 /
10, 0, 9, 14, 6, 3, 15, 5, 1, 13, 12, 7, 11, 4, 2, 8,
13, 7, 0, 9, 3, 4, 6, 10, 2, 8, 5, 14, 12, 11, 15, 1,
13, 6, 4, 9, 8, 15, 3, 0, 11, 1, 2, 12, 5, 10, 14, 7,
1, 10, 13, 0, 6, 9, 8, 7, 4, 15, 14, 3, 11, 5, 2, 12,
/ S4 /
7, 13, 14, 3, 0, 6, 9, 10, 1, 2, 8, 5, 11, 12, 4, 15,
13, 8, 11, 5, 6, 15, 0, 3, 4, 7, 2, 12, 1, 10, 14, 9,
10, 6, 9, 0, 12, 11, 7, 13, 15, 1, 3, 14, 5, 2, 8, 4,
3, 15, 0, 6, 10, 1, 13, 8, 9, 4, 5, 11, 12, 7, 2, 14,
/ S5 /
2, 12, 4, 1, 7, 10, 11, 6, 8, 5, 3, 15, 13, 0, 14, 9,
14, 11, 2, 12, 4, 7, 13, 1, 5, 0, 15, 10, 3, 9, 8, 6,
4, 2, 1, 11, 10, 13, 7, 8, 15, 9, 12, 5, 6, 3, 0, 14,
11, 8, 12, 7, 1, 14, 2, 13, 6, 15, 0, 9, 10, 4, 5, 3,
/ S6 /
12, 1, 10, 15, 9, 2, 6, 8, 0, 13, 3, 4, 14, 7, 5, 11,
10, 15, 4, 2, 7, 12, 9, 5, 6, 1, 13, 14, 0, 11, 3, 8,
9, 14, 15, 5, 2, 8, 12, 3, 7, 0, 4, 10, 1, 13, 11, 6,
4, 3, 2, 12, 9, 5, 15, 10, 11, 14, 1, 7, 6, 0, 8, 13,
/ S7 /
4, 11, 2, 14, 15, 0, 8, 13, 3, 12, 9, 7, 5, 10, 6, 1,
13, 0, 11, 7, 4, 9, 1, 10, 14, 3, 5, 12, 2, 15, 8, 6,
1, 4, 11, 13, 12, 3, 7, 14, 10, 15, 6, 8, 0, 5, 9, 2,
6, 11, 13, 8, 1, 4, 10, 7, 9, 5, 0, 15, 14, 2, 3, 12,
/ S8 /
13, 2, 8, 4, 6, 15, 11, 1, 10, 9, 3, 14, 5, 0, 12, 7,
1, 15, 13, 8, 10, 3, 7, 4, 12, 5, 6, 11, 0, 14, 9, 2,
7, 11, 4, 1, 9, 12, 14, 2, 0, 6, 10, 13, 15, 3, 5, 8,
2, 1, 14, 7, 4, 10, 8, 13, 15, 12, 9, 0, 3, 5, 6, 11
};
/ 32-bit permutation function P used on the output of the S-boxes /
static byte p32i[] = {
16, 7, 20, 21,
29, 12, 28, 17,
1, 15, 23, 26,
5, 18, 31, 10,
2, 8, 24, 14,
32, 27, 3, 9,
19, 13, 30, 6,
22, 11, 4, 25
};
#endif
/ permuted choice table (key) /
static const byte pc1[] = {
57, 49, 41, 33, 25, 17, 9,
1, 58, 50, 42, 34, 26, 18,
10, 2, 59, 51, 43, 35, 27,
19, 11, 3, 60, 52, 44, 36,
63, 55, 47, 39, 31, 23, 15,
7, 62, 54, 46, 38, 30, 22,
14, 6, 61, 53, 45, 37, 29,
21, 13, 5, 28, 20, 12, 4
};
/ number left rotations of pc1 /
static const byte totrot[] = {
1,2,4,6,8,10,12,14,15,17,19,21,23,25,27,28
};
/ permuted choice key (table) /
static const byte pc2[] = {
14, 17, 11, 24, 1, 5,
3, 28, 15, 6, 21, 10,
23, 19, 12, 4, 26, 8,
16, 7, 27, 20, 13, 2,
41, 52, 31, 37, 47, 55,
30, 40, 51, 45, 33, 48,
44, 49, 39, 56, 34, 53,
46, 42, 50, 36, 29, 32
};
/ End of DES-defined tables /
/ bit 0 is left-most in byte /
static const int bytebit[] = {
0200,0100,040,020,010,04,02,01
};
/ Set key (initialize key schedule array) /
DES::DES(const byte key, CipherDir dir)
: k(32)
{
SecByteBlock buffer(56+56+8);
byte const pc1m=buffer; / place to modify pc1 into /
byte const pcr=pc1m+56; / place to rotate pc1 into /
byte const ks=pcr+56;
register int i,j,l;
int m;
for (j=0; j<56; j++) { / convert pc1 to bits of key /
l=pc1[j]-1; / integer bit location /
m = l & 07; / find bit /
pc1m[j]=(key[l>>3] & / find which key byte l is in /
bytebit[m]) / and which bit of that byte /
1 : 0; / and store 1-bit result /
}
for (i=0; i<16; i++) { / key chunk for each iteration /
memset(ks,0,8); / Clear key schedule /
for (j=0; j<56; j++) / rotate pc1 the right amount /
pcr[j] = pc1m[(l=j+totrot[i])<(j<28 28 : 56) l: l-28];
/ rotate left and right halves independently /
for (j=0; j<48; j++){ / select bits individually /
/ check bit that goes to ks[j] /
if (pcr[pc2[j]-1]){
/ mask it in if it's there /
l= j % 6;
ks[j/6] |= bytebit[l] >> 2;
}
}
/ Now convert to odd/even interleaved form for use in F /
k[2i] = ((word32)ks[0] << 24)
| ((word32)ks[2] << 16)
| ((word32)ks[4] << 8)
| ((word32)ks[6]);
k[2i+1] = ((word32)ks[1] << 24)
| ((word32)ks[3] << 16)
| ((word32)ks[5] << 8)
| ((word32)ks[7]);
}
if (dir==DECRYPTION) // reverse key schedule order
for (i=0; i<16; i+=2)
{
std::swap(k[i], k[32-2-i]);
std::swap(k[i+1], k[32-1-i]);
}
}
/ End of C code common to both versions /
/ C code only in portable version /
// Richard Outerbridge's initial permutation algorithm
/
inline void IPERM(word32 &left, word32 &right)
{
word32 work;
work = ((left >> 4) ^ right) & 0x0f0f0f0f;
right ^= work;
left ^= work << 4;
work = ((left >> 16) ^ right) & 0xffff;
right ^= work;
left ^= work << 16;
work = ((right >> 2) ^ left) & 0x33333333;
left ^= work;
right ^= (work << 2);
work = ((right >> 8) ^ left) & 0xff00ff;
left ^= work;
right ^= (work << 8);
right = rotl(right, 1);
work = (left ^ right) & 0xaaaaaaaa;
left ^= work;
right ^= work;
left = rotl(left, 1);
}
inline void FPERM(word32 &left, word32 &right)
{
word32 work;
right = rotr(right, 1);
work = (left ^ right) & 0xaaaaaaaa;
left ^= work;
right ^= work;
left = rotr(left, 1);
work = ((left >> 8) ^ right) & 0xff00ff;
right ^= work;
left ^= work << 8;
work = ((left >> 2) ^ right) & 0x33333333;
right ^= work;
left ^= work << 2;
work = ((right >> 16) ^ left) & 0xffff;
left ^= work;
right ^= work << 16;
work = ((right >> 4) ^ left) & 0x0f0f0f0f;
left ^= work;
right ^= work << 4;
}
/
// Wei Dai's modification to Richard Outerbridge's initial permutation
// algorithm, this one is faster if you have access to rotate instructions
// (like in MSVC)
inline void IPERM(word32 &left, word32 &right)
{
word32 work;
right = rotl(right, 4U);
work = (left ^ right) & 0xf0f0f0f0;
left ^= work;
right = rotr(right^work, 20U);
work = (left ^ right) & 0xffff0000;
left ^= work;
right = rotr(right^work, 18U);
work = (left ^ right) & 0x33333333;
left ^= work;
right = rotr(right^work, 6U);
work = (left ^ right) & 0x00ff00ff;
left ^= work;
right = rotl(right^work, 9U);
work = (left ^ right) & 0xaaaaaaaa;
left = rotl(left^work, 1U);
right ^= work;
}
inline void FPERM(word32 &left, word32 &right)
{
word32 work;
right = rotr(right, 1U);
work = (left ^ right) & 0xaaaaaaaa;
right ^= work;
left = rotr(left^work, 9U);
work = (left ^ right) & 0x00ff00ff;
right ^= work;
left = rotl(left^work, 6U);
work = (left ^ right) & 0x33333333;
right ^= work;
left = rotl(left^work, 18U);
work = (left ^ right) & 0xffff0000;
right ^= work;
left = rotl(left^work, 20U);
work = (left ^ right) & 0xf0f0f0f0;
right ^= work;
left = rotr(left^work, 4U);
}
// Encrypt or decrypt a block of data in ECB mode
void DES::ProcessBlock(const byte inBlock, byte outBlock) const
{
word32 l,r,work;
#ifdef IS_LITTLE_ENDIAN
l = byteReverse((word32 )inBlock);
r = byteReverse((word32 )(inBlock+4));
#else
l = (word32 )inBlock;
r = (word32 )(inBlock+4);
#endif
IPERM(l,r);
const word32 kptr=k;
for (unsigned i=0; i<8; i++)
{
work = rotr(r, 4U) ^ kptr[4i+0];
l ^= Spbox[6][(work) & 0x3f]
^ Spbox[4][(work >> 8) & 0x3f]
^ Spbox[2][(work >> 16) & 0x3f]
^ Spbox[0][(work >> 24) & 0x3f];
work = r ^ kptr[4i+1];
l ^= Spbox[7][(work) & 0x3f]
^ Spbox[5][(work >> 8) & 0x3f]
^ Spbox[3][(work >> 16) & 0x3f]
^ Spbox[1][(work >> 24) & 0x3f];
work = rotr(l, 4U) ^ kptr[4i+2];
r ^= Spbox[6][(work) & 0x3f]
^ Spbox[4][(work >> 8) & 0x3f]
^ Spbox[2][(work >> 16) & 0x3f]
^ Spbox[0][(work >> 24) & 0x3f];
work = l ^ kptr[4i+3];
r ^= Spbox[7][(work) & 0x3f]
^ Spbox[5][(work >> 8) & 0x3f]
^ Spbox[3][(work >> 16) & 0x3f]
^ Spbox[1][(work >> 24) & 0x3f];
}
FPERM(l,r);
#ifdef IS_LITTLE_ENDIAN
(word32 )outBlock = byteReverse(r);
(word32 )(outBlock+4) = byteReverse(l);
#else
(word32 )outBlock = r;
(word32 )(outBlock+4) = l;
#endif
}
void DES_EDE_Encryption::ProcessBlock(byte inoutBlock) const
{
eProcessBlock(inoutBlock);
dProcessBlock(inoutBlock);
eProcessBlock(inoutBlock);
}
void DES_EDE_Encryption::ProcessBlock(const byte inBlock, byte outBlock) const
{
eProcessBlock(inBlock, outBlock);
dProcessBlock(outBlock);
eProcessBlock(outBlock);
}
void DES_EDE_Decryption::ProcessBlock(byte inoutBlock) const
{
dProcessBlock(inoutBlock);
eProcessBlock(inoutBlock);
dProcessBlock(inoutBlock);
}
void DES_EDE_Decryption::ProcessBlock(const byte inBlock, byte outBlock) const
{
dProcessBlock(inBlock, outBlock);
eProcessBlock(outBlock);
dProcessBlock(outBlock);
}
void TripleDES_Encryption::ProcessBlock(byte inoutBlock) const
{
e1ProcessBlock(inoutBlock);
dProcessBlock(inoutBlock);
e2ProcessBlock(inoutBlock);
}
void TripleDES_Encryption::ProcessBlock(const byte inBlock, byte outBlock) const
{
e1ProcessBlock(inBlock, outBlock);
dProcessBlock(outBlock);
e2ProcessBlock(outBlock);
}
void TripleDES_Decryption::ProcessBlock(byte inoutBlock) const
{
d1ProcessBlock(inoutBlock);
eProcessBlock(inoutBlock);
d2ProcessBlock(inoutBlock);
}
void TripleDES_Decryption::ProcessBlock(const byte inBlock, byte outBlock) const
{
d1ProcessBlock(inBlock, outBlock);
eProcessBlock(outBlock);
d2ProcessBlock(outBlock);
}
NAMESPACE_END
程序运行如下：
Java写DES一般用现成的类库，而C++来完成加密算法工作都是用openssl库来实现的。
openssl库调用不算很难，编译网上也有 *** 作流程。
当不同语言实现加密解密 *** 作的时候，注意一下反馈模式和填充模式就行。
常用的反馈模式是ECB和CBC，你这套代码是用的ECB就是无反馈模式，这个就可以不用考虑了。而填充模式标准的填充方法是pkcs#5标准，如果按照这种标准填充的，那什么语言只要数据对应，都没问题，因为算法的实现是相同的。
标准的DES密钥长度为64bit，密钥每个字符占7bit，外加1bit的奇偶校验，64/(7+1)=8。
所以必须是8个字符也只能是8个字符。
但
NET
里
DESCryptoServiceProvider
这个类是微软已经封装好的了，如果密钥长度不足，会以
PKCS7Padding
方式补足位。
补足位原理参考：>
以上就是关于寻找一个DES加密算法的dll文件，在VB和C#里加密结果一样全部的内容，包括:寻找一个DES加密算法的dll文件，在VB和C#里加密结果一样、des算法加密解密的实现、des加密算法(c/c++)等相关内容解答，如果想了解更多相关内容，可以关注我们，你们的支持是我们更新的动力！
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