
假设你的文本是纯英文文字档 ( 不是 unicode )
my @files = @ARGV;
foreach my $file ( @files ) {
open F, $file or die "Can't open $file$/";
my ( $lines, $words, $chars ) ;
my $rawchars = -s $file;
while (my $line = <F> ) {
chomp $line;
my @w = split /[^\w]+/, $line;
$chars += length ( join " ", @w ) ;
$words += @w;
$lines++;
}
print "$file has $lines lines, $words words, $chars chars(true char), $rawchars rawchars(include space, punc, enter)$/";
}
你所说的保存是什么意思?我保存到数组里好了~
open IN, “<”, "datatxt" or die;
my @a = <IN>;
close IN;
第2题
chomp($str=<STDIN>);
my @array=split/[ ,]/,$str;
my $mx = $array[0];
for my $e(@array) {$mx = $e if ($e > $mx);}
print "最大值为$mx";
第3题
chomp($str=<STDIN>);
my @array=split/[ ,]/,$str;
my @sorted_num=sort{$a<=>$b}@array;
my $string=join(",",@sorted_num);
print "排序后的数列为:$string";
第4题
chomp($str=<STDIN>);
my @array=split//,$str;
my %ha;
my @uniq=grep{++$ha{$_}<2}@array;
my $size=@array;
my $n;my $foundno;my $regex;my $freq;
print "氨基酸\t频数\t频率\n";
for($n=0;$n<@uniq;$n++){
$regex=@uniq[$n];
$foundno=0;
$foundno++ while($str=~m/$regex/g);
$freq=$foundno100/$size;
print "$regex\t$foundno\t$freq%\n";
}
#!/usr/bin/perl
my $a = << 'ATXT';
NC_1 125 A
NC_2 657 C
Un 147 G
Un 321 A
ATXT
my $b = << 'BTXT';
NW_1 1 200 0
NW_2 201 300 500
NW_3 301 800 1000
BTXT
open CCC,"> d:/ctxt";
my @a = split(/\n/,$a);
my @b = split(/\n/,$b);
foreach $c (@a){
undef $m;
if($c =~/^Un\s+(\d+)/){
$m = $1;
foreach $d (@b){
my @e = split(/\s+/,$d);
if($m > $e[1] && $m < $e[2]){
my $f = $m - $e[3];
print CCC "$e[0] $f\n";
print "$e[0] $f\n";
}
}
}else{
print CCC "$c\n";
print "$c\n";
}
}
close CCC;
open(FD,$ARGV[0]);
my(@c,$g,$e,$l);#count,greater,equal,less
my($s,$n,$i);
$i=1;
while($s=<FD>){
$s=~s/[^a]//g;
$n=length($s);
$c[$i]=$n;
$g++ if ($n>5);
$e++ if ($n==5);
$l++ if ($n<5);
$i++;
}
close(FD);
$n=$g+$e+$l;
print "a>5 $g "($g100/$n)"%\n";
print "a=5 $e "($e100/$n)"%\n";
print "a<5 $l "($l100/$n)"%\n";
上面的程序测试通过,完全满足你的要求,结果是正确的。
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