通过列表理解拼合列表

>>> from collections import Iterable>>> from itertools import chain

单线：

>>> list(chain.from_iterable(item if isinstance(item,Iterable) and         not isinstance(item, basestring) else [item] for item in lis))[1, 2, 3, 4, 5, 6, 7, 8]

可读版本：

>>> def func(x):        #use `str` in py3.x ...     if isinstance(x, Iterable) and not isinstance(x, basestring): ...         return x...     return [x]... >>> list(chain.from_iterable(func(x) for x in lis))[1, 2, 3, 4, 5, 6, 7, 8]#works for strings as well>>> lis = [[1, 2, 3], [4, 5, 6], 7, 8, "foobar"]>>> list(chain.from_iterable(func(x) for x in lis))         [1, 2, 3, 4, 5, 6, 7, 8, 'foobar']

使用嵌套列表理解：（与相比要慢一些

itertools.chain

>>> [ele for item in (func(x) for x in lis) for ele in item][1, 2, 3, 4, 5, 6, 7, 8, 'foobar']