Python中的音节计数

Python中的音节计数

问题是您给它提供了大写的字符串，但是只比较了小写的值。可以通过添加

word = word.lower()

到函数的开头来解决此问题。

def syllable_count(word):    word = word.lower()    count = 0    vowels = "aeiouy"    if word[0] in vowels:        count += 1    for index in range(1, len(word)):        if word[index] in vowels and word[index - 1] not in vowels: count += 1    if word.endswith("e"):        count -= 1    if count == 0:        count += 1    return countprint(syllable_count('HAIRY'))  # prints "2"