
尝试
SELECt messages.*, T2.photoFROM messagesLEFT JOIN (SELECt userid, MAX(id) AS maxidFROM tblimagesGROUP BY userid) AS T1ON messages.user_id = T1.useridLEFT JOIN tblimages AS T2ON T2.id = T1.maxidORDER BY messages.msg_id DESC
会在tblimages中为每个用户找到max(id),然后使用该值将每个用户加入该用户的最新照片。
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