比较两个json数组

比较两个json数组

不能保证以相同的方式序列化JSON对象，也不能保证属性以相同的顺序进行序列化，使用

JSON.stringify

并不是测试对象相等性的好方法。

一个更好的例子是这样的函数（前一段时间在互联网上找到，希望我能感谢原始作者）

function equals ( x, y ) {    // If both x and y are null or undefined and exactly the same    if ( x === y ) {        return true;    }    // If they are not strictly equal, they both need to be Objects    if ( ! ( x instanceof Object ) || ! ( y instanceof Object ) ) {        return false;    }    // They must have the exact same prototype chain, the closest we can do is    // test the constructor.    if ( x.constructor !== y.constructor ) {        return false;    }    for ( var p in x ) {        // Inherited properties were tested using x.constructor === y.constructor        if ( x.hasOwnProperty( p ) ) { // Allows comparing x[ p ] and y[ p ] when set to undefined if ( ! y.hasOwnProperty( p ) ) {     return false; } // If they have the same strict value or identity then they are equal if ( x[ p ] === y[ p ] ) {     continue; } // Numbers, Strings, Functions, Booleans must be strictly equal if ( typeof( x[ p ] ) !== "object" ) {     return false; } // Objects and Arrays must be tested recursively if ( !equals( x[ p ],  y[ p ] ) ) {     return false; }        }    }    for ( p in y ) {        // allows x[ p ] to be set to undefined        if ( y.hasOwnProperty( p ) && ! x.hasOwnProperty( p ) ) { return false;        }    }    return true;},