poj 1650 Integer Approximation

poj 1650 Integer Approximation,第1张

poj 1650 Integer Approximation
#include <iostream>#include <cstdlib>#include <cstring>#include <cstdio>#include <cmath>using namespace std;struct Elem{    int a, b;}ans;double n;int lim;int binarysearch(int x){    int l = 1;    int r = min(lim, x * 10);    while (l < r)    {        int mid = (l + r) / 2;        if (mid * 1.0 / x < n) l = mid + 1;        else r = mid;    }    return l;}void make(int a, int b){    if (abs(a * 1.0 / b - n) < abs(ans.a * 1.0 / ans.b - n))    {        ans.a = a;        ans.b = b;    }}int main(){    scanf("%lf%d", &n, &lim);    ans.a = (int)(n + 0.5);    ans.b = 1;    if (ans.a == 0)        ans.a = 1;    if (ans.a > lim)        ans.a = lim;    for (int i = 2; i <= lim; i++)    {        int x = binarysearch(i);        make(x, i);        if (x > 1) make(x - 1, i);    }    printf("%d %dn", ans.a, ans.b);    return 0;}

欢迎分享,转载请注明来源:内存溢出

原文地址:https://54852.com/zaji/4897349.html

(0)
打赏 微信扫一扫微信扫一扫 支付宝扫一扫支付宝扫一扫
上一篇 2022-11-12
下一篇2022-11-12

发表评论

登录后才能评论

评论列表(0条)

    保存