Linux用while循环求1+2+3+....+100的和 求解啊

#!/bin/bash

i=1

sum=0

while [ $i -le 100 ]

do

sum=$((sum+i))

((i++))

done

echo $sum

#!/bin/bash

[ $# -ne 1 ] &&exit 1 #判断参数个数

[ "$1" -le 0 ] &&exit 1 #判断参数合法性

sum=0

for (( i=1i<=$1i=i+1 ))

do

read -p "Input number #$i: " num[$i]

sum=$((sum+num[$i]))

done

average=$((sum/$1))

echo "sum: $sum"

echo "average: $average"

exit 0

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