
Sub ReverseDigit()
Dim number As Integer, digit As Integer
number = Val(InputBox("请输入一个非负整数"))
If (number <0) Then
Debug.Print number"不是非负整数,请输入非负整数"
Exit Sub
End If
Debug.Print number"早巧芹的逆宽手序数为:"
Do
digit = number Mod 10 '(陆毕1)
number = number \ 10 '(2)
Debug.Print Format(digit, "#")
Loop While (number >0) '(3)
Debug.Print
End Sub
Private Sub Command1_Click()Dim i As Integer, n As Integer
Dim a() As Integer
n = InputBox("请输差告入数的个数")
ReDim a(n)
For i = 1 To n
a(i) = InputBox("请输入第" &i &"个纯或数")
Print a(i)
Next i
Sub sort(a() As Integer, n As Integer)
For i = 1 To n / 2
x = a(i)
a(i) = a(n - i + 1)
a(n - i + 1) = x
Next i
For i = 1 To n
Print a(i)
Next
End Sub
你所说的反序是从大到小,还是把数组元素顺序倒过来?上以上程序满足后者
从大做庆伍到小这样
Sub sort(a() As Integer, n As Integer)
Dim i As Integer, j As Integer, temp As Integer
For i = 1 To n - 1
k = i
For j = i + 1 To n
If a(j) >a(k) Then k = j
Next j
temp = a(k): a(k) = a(i): a(i) = temp
Next i
For i = 1 To n
Print a(i)
Next
End Sub
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