c语言数组计算程序设计

写完了~~LZ看下吧~

#include <stdio.h>

#include <stdlib.h>

int n,p,a[33],b[33],mid,move

void dfs(int deep,int sum)

{

int i

if (deep>n) return

if (sum>mid+move) return

else

{

if (deep>0 &&abs(sum-mid)<=move)

{

for (i=1i<=ni++)

{

if (b[i]==1) printf("%d ",i)

p++

}

printf("\n")

}

for (i=1i<=ni++)

{

if (b[i]==0)

{

b[i]=1

sum=sum+a[i]

dfs(deep+1,sum)

sum=sum-a[i]

b[i]=0

}

}

}

}

int main ()

{

int i,j

printf("请输入数组中元素个数(n<=32): ")

scanf("%d",&n)

printf("\n")

printf("请塌态依次输入 %d 个数 (0-200): ",n)

for (i=1i<=ni++)

{

scanf("%d",&a[i])

b[i]=0

}

printf("\厅衫谈n")

printf("请输入扮碰中心值 : ")

scanf("%d",&mid)

printf("\n")

printf("请输入正负偏差值 : ")

scanf("%d",&move)

abs(move)

printf("\n")

printf("----------我是华丽的分割线----------\n")

dfs(0,0)

if (p==0) printf("无解啊！！！！\n")

return 0

}

打印输出这种的效果，弊运不对的话再微调修改下：

#include <stdio.h>

#include <stdlib.h>

int main()

{

int i = 0//存放行

int j = 0//存放孝森列

double sum//存放对角线数据和

//定义一个整型二维数组array并初始化

int array[5][5] = {

{1,2,3,4,5},

{6,7,8,9,10},

{11,12,13,14,15},

{16,17,18,19,20},

{21,22,23,24,25},}

//以5x5的矩阵形式输出数巧卜亩组

for(i=0i<5i++)

{

for(j=0j<5j++)

{

//            printf("第%d行第%d列元素是：%4d\t",i+1,j+1,array[i][j])

printf("%4d",array[i][j])//打印输出矩阵数组

if(j==4)

{

printf("\n")

}

if(i == j || 4-i == 4-j)    //计算对角线之和

{

sum += array[i][j]

sum += array[4-i][4-j]

}

}

}

printf("\n对角线之和是：%4.lf\n",sum)

return 0

}

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