
{
array[1] = 1
array[2] = 2
array[3] = 3
array[4] = 4
array[5] = 5
for (i = 1 i <= 5 ++i) {
print array[i]
}
}'
split(s,a,fs) 以fs为指定分隔符将字符串s分割成一个数组a awk 'BEGIN{print split("aswd|sawa|eee",Ti,"|"),Ti[1]}'shell没有数组,不过下面的实施方式,不知道对你有帮组不?#!/bin/sh
i=0
for filename in `ls`
do
echo "myfile$i=$filename" >>./mydata
i=`expr $i + 1`
done
eval `cat ./mydata`
#以下演示
b=0
cat ./mydata | while read line
do
myarray="myfile$b"
eval echo "cp \$$myarray to some dir"
b=`expr $b + 1`
done
rm -f ./mydata
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