
machine1$ cd ..
machine1$ mv repo repo.old
machine1$ git clone --bare repo.old repo
这是个很恶心的问题。我乍一看觉得应该是655我再vc6.0上实验(Debug模式)发现结果是555(vc6debug模式汇编代码)004013A8movdwordptr[ebp-4],5;先将5给[ebp-4]004013AFmoveax,dwordptr[ebp-4];再将5传给eax004013B2pusheax将eax压栈004013B3movecx,dwordptr[ebp-4];将5==>ecx004013B6movdwordptr[ebp-20h],ecx将5==>[ebp-20h]004013B9movedx,dwordptr[ebp-20h]将5==>edx004013BCpushedx将5压栈004013BDmoveax,dwordptr[ebp-4]004013C0pusheax;还是将5压栈004013C1pushoffsetstring"%d%d%d\n"(00426000)004013C6movecx,dwordptr[ebp-4]004013C9addecx,1004013CCmovdwordptr[ebp-4],ecx004013CFcallprintf(00401620)004013D4addesp,10h显而易见结果是555了。不过我为了验证又在release下运行了一把,发现结果竟然是656(vc6release模式汇编代码)push6push5push6push407130hcall00401017addesp,10hxoreax,eaxret晕。编译器给优化了。。。显而易见结果是656了还是不死心再看看linux下gcc编译的发现结果也是656(gccdebug)00401326|.C744241C050>movdwordptr[esp+1C],5|现将5放到[esp+1c]中0040132E|.8B44241Cmoveax,dwordptr[esp+1C]|5==>eax00401332|.FF44241Cincdwordptr[esp+1C]|[esp+1c]++[esp+1c]等于6了00401336|.8B54241Cmovedx,dwordptr[esp+1C]|6==>edx0040133A|.8954240Cmovdwordptr[esp+C],edx|这相当于pushedx也就是将6压栈0040133E|.89442408movdwordptr[esp+8],eax|这相当于pusheax也就是将5压栈00401342|.8B44241Cmoveax,dwordptr[esp+1C]|将6放到eax中00401346|.89442404movdwordptr[esp+4],eax|这相当于pusheax也就是将6压栈0040134A|.C70424243040>movdwordptr[esp],00403024|ASCII"%d%d%d",LF00401351|.E836060000call\printf所以结果是656啦gcc的release和debug一样。。还是不死心。有在vc2005的debug下运行了一把发现结果是656??(vc2005debug汇编代码)00411B4Cmovdwordptr[ebp-0Ch],5;5==>[EBP-0c]00411B53moveax,dwordptr[ebp-0Ch]。;5==>eax00411B56movdwordptr[ebp-1194h],eax5==>[ebp-1194h]00411B5Cmovecx,dwordptr[ebp-0Ch]5==>ecx00411B5Faddecx,1ecx++ecx==600411B62movdwordptr[ebp-0Ch],ecx6==>[ebp-0Ch]00411B65movesi,esp00411B67movedx,dwordptr[ebp-0Ch]6==>edx00411B6Apushedx将6压栈00411B6Bmoveax,dwordptr[ebp-1194h];5==>eax00411B71pusheax将5压栈00411B72movecx,dwordptr[ebp-0Ch];6==>ecx00411B75pushecx将6压栈00411B76pushoffsetstring"%d%d%d\n"(41E9ACh)00411B7Bcalldwordptr[__imp__printf(423780h)]00411B81addesp,10h结果是656唉。看来结果就是656啦。。vc2005和以后版本都注意到了这个问题。我也说不上哪个正确,你又相信哪个呢?欢迎分享,转载请注明来源:内存溢出
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