"stdio.h"对ATM机器的模拟就是一个对队列的模拟下面代码在VC6环境下调郑野试雹隐已经通过了其中有个缺陷就是因为代码执行速度过快导致二次执行根据时间随机出来的数字都是一样的因此你可以自己加上一个延迟子程序部分功能已经注释了#include
"stdlib.h"#include
"time.h"#define
OK
1#define
ERROR
0
typedef
struct
node{
int
number
struct
node*
next}*Lnode
typedef
struct
list{
node
*head,*rear}*Plist
//模拟
ATM开业bool
ListInit(Plist
list){
Lnode
p
p
=
(Lnode)malloc(sizeof(Lnode))
list->head
=
p
list->rear
=
list->head
list->head->next
=
NULL
if(list->head!=NULL)
return
ERROR
else
return
OK}
//模拟
有客户排队bool
ListInsert(Plist
list,int
number){
Lnode
p
p
=
(Lnode)malloc(sizeof(Lnode))
if(p==NULL)
return
ERROR
else
{
p->number
=
number
p->next
=
NULL
list->rear->next
=
p
list->rear
=
p
return
OK
}}
//模拟
客户办完事离开bool
ListDelete(Plist
list){
Lnode
p
if(list->head
==list->rear)
return
ERROR
else
{
p
=
list->head->next
list->head->next
=
p->next
list->rear
=
list->head
//
free(p)
return
OK
}}
void
sand(int*
gettime,int*
needtime){
srand(time(NULL))
*gettime
=
rand()%100
srand(time(NULL))
*needtime
=rand()%100}
//模拟客户到达事件void
CustomerArrived(Plist
list,int
gettime,int
needtime,int
kehu,int
time){
int
nextgettime,nextneedtime
sand(&nextgettime,&nextneedtime)
while(needtime>0
&&
nextgettime>0
&&
time>0)
{
needtime
--
nextgettime
--
time
--
}
if(nextgettime
==
0
&&
needtime>0
&&time>0)
{
kehu++
ListInsert(list,kehu)
while(needtime>0
&&
time>0)
{
needtime--
time
--
}
ListDelete(list)
CustomerArrived(list,nextgettime,nextneedtime,kehu,time)
}
if(needtime
==0
&&
nextgettime>0
&&
time>0)
{
ListDelete(list)
while(nextgettime>0
&&
time>0)
{
nextgettime--
time
--
}
kehu++
ListInsert(list,kehu)
//未删除
，list未传递进去
CustomerArrived(list,nextgettime,nextneedtime,kehu,time)
}
if(time
==0)
{
printf("ATM关门,请明天在来!\n")
return
}}
main(){
list
list
int
i
=
10000
/源丛厅/ATM机器每天工作时间
int
kehu
=
0
//客户标号
int
gettime,needtime
ListInit(&list)
//ATM开业
sand(&gettime,&needtime)
ListInsert(&list,kehu)
CustomerArrived(&list,gettime,needtime,kehu,i)
getchar()
}
#include <stdio.h>#include <stdlib.h>
#include <conio.h>
#include <string.h>
void regist()
void login()
void quite()
void inputpassword(char mima[])
void service()
struct bank
{
char name[20]
char password[7]
int account
double money
}kehu
int find
int a[10]
struct bank one
FILE *fp
void main()
{
int i
int t=1
for(i=0i<100i++)
{
printf("\t\t\t\t\t\t欢迎使用青软ATM系统\n")
printf("\t\t\t\t\t\t正在进入主界面，请稍等")
int j
for(j=1j<tj++)
{
printf(".")
}
t++
if(t==10)
{
t=1
}
printf("\n\t\t\t\t\t\t%d%%",i)
system("cls")
}
while(1)
{
printf("\t\橘散t\t\t\t\t服务类型: \n")
printf("\t\t\t\t\t\t[a]: 用户注册\n")
printf("神源\t\t\t\t\t\t[b]: 用户登录\n")
printf("\t\t\t\t\t\t[c]: 退出系统\n")
printf("\t\t\t\t\t\t请选择服务： ")
fflush(stdin)
char xz
scanf("%c",&xz)
if(xz=='a'||xz=='A')
{
regist()
} else if (xz=='b'||xz=='B')
{
login()
} else if(xz=='c'||xz=='C')
{
quite()
} else
{
printf("输入有误，请重新输入")
}
getch()
system("cls")
}
}
void inputpassword(char mima[])
{
int i=0
char ch
while(1)
{
ch=getch()
if(ch!='\r')
{
if(ch!='\b'){
mima[i]=ch
i++
printf("*")
}else{
if(i>0){
i--
printf("\b \b")
}
}
}else{
break
}
}
mima[i]='\0'
printf("\n")
}
void regist()
{
fp=fopen("atm.txt","ab+")
if(fp==NULL)
{
printf("\n\t\t\t文件打开失败!")
return
}
system("cls")
printf("\t\t\t现在执行的是注册函数的使用\n")
printf("\t\t请输入用户名: ")
fflush(stdin)
gets(kehu.name)
char password1[7]
while(1)
{
while(1)
{
printf("\n\n\t\t请输入密码：")
fflush(stdin)
inputpassword(kehu.password)
int n=strlen(kehu.password)
if(n==6)
{
break
}else
{
printf("\n\t\t密码必须为6位!")
}
}
printf("\n\t\t请输入正确密码!: ")
fflush(stdin)
inputpassword(password1)
if(strcmp(kehu.password,password1)==0)
{
break
}else{
printf("\n\n\t\t两次密码必须相同！")
}
}
rewind(fp)
struct bank k
if(fread(&k,sizeof(struct bank),1,fp)==1)
{
fseek(fp,-sizeof(k),2)
fread(&k,sizeof(k),1,fp)
kehu.account=k.account+1
}else{
kehu.account=20170001
}
kehu.money=0
fseek(fp,0,2)
fwrite(&kehu,sizeof(struct bank),1,fp)
fclose(fp)
printf("\n\n\t\t开户成功! ")
printf("\游伍态n\t\t您的账号为%d!",kehu.account)
printf("\n\t\t现在请您重新登录!")
}
void searchmoney()
{
system("cls")
printf("您现在使用的是查询余额功能: \n")
printf("\n\n\t\t您的余额是%0.2lf",one.money)
}
void savemoney()
{
system("cls")
double inmoney
printf("请您选择您要存款的金额 \n")
scanf("%lf",&inmoney)
int q
int r=1
for(q=0q<100q++)
{
int w
for(w=1w<rw++)
{
printf(".")
}
r++
if(r==10)
{
r=1
}
printf("\n\t\t\t\t\t\t正在存款%d%%",q)
system("cls")
}
one.money=one.money+inmoney
fseek(fp,-sizeof(one),1)
fwrite(&one,sizeof(one),1,fp)
printf("\n\n\t\t\t\t\t\t您已存款成功!")
}
void withdrawalmoney()
{
system("cls")
double outputsomemoney
printf("请您选择您要取款的金额 \n")
scanf("%lf",&outputsomemoney)
if(one.money<outputsomemoney){
printf("您的余额已不足，请您注意!")
}else {
int q
int r=1
for(q=0q<100q++)
{
int w
for(w=1w<rw++)
{
printf(".")
}
r++
if(r==10)
{
r=1
}
printf("\n\t\t\t\t\t\t正在取款%d%%",q)
system("cls")
}
one.money=one.money-outputsomemoney
fseek(fp,-sizeof(one),1)
fwrite(&one,sizeof(one),1,fp)
printf("\n\n\t\t\t\t\t\t您已取款成功!请点清钞票!")
printf("\n\n\t\t\t\t\t\t您现在的余额为%lf",one.money)
}
}
void transfermoney()
{
system("cls")
int duifang
int qian
fflush(stdin)
printf("\n\n\n\t\t您现在使用的是转账功能")
printf("\n\t\t\t请输入您要转账的账户:")
scanf("%d",&duifang)
int n=ftell(fp)
rewind(fp)
int flag=0
struct bank temp
while(fread(&temp,sizeof(temp),1,fp)==1)
{
if(temp.account==duifang)
{
flag=1
break
}
}
if(flag==1)
{
printf("请输入转账金额：")
scanf("%d",&qian)
if(one.money>=qian)
{
int q
int r=1
for(q=0q<100q++)
{
int w
for(w=1w<rw++)
{
printf(".")
}
r++
if(r==10)
{
r=1
}
printf("\n\t\t\t\t\t\t正在转账，请稍后!%d%%",q)
system("cls")
}
temp.money=temp.money+qian
fseek(fp,-sizeof(temp),1)
fwrite(&temp,sizeof(temp),1,fp)
one.money=one.money-qian
fseek(fp,n-sizeof(one),0)
fwrite(&one,sizeof(one),1,fp)
printf("\n\t\t\t\t转账成功!")
}else{
printf("\n\t\t\t\t您的余额已不足!")
}
}
}
void xiugai(){
system("cls")
printf("\n\n\t\t 现在进行的是修改密码功能\n")
char oldpassword[7]
char newpassword[7]
char newpassword1[7]
int i
for(i=0i<3i++){
printf("\n\t\t\t 请输入旧密码：\n")
inputpassword(oldpassword)
if(strcmp(oldpassword,one.password)==0){
printf("\n\t\t\t 输入成功！\n")
break
}else{
printf("\n\t\t\t 密码输入有误，请重新输入！\n")
}
}
if(i<3){
while(1){
printf("\n\t\t\t 请输入您的新密码：\n")
inputpassword(newpassword)
printf("\n\t\t\t 请输入您的确认密码：\n ")
inputpassword(newpassword1)
if(strcmp(newpassword,newpassword1)==0){
strcpy(one.password,newpassword)
fseek(fp,-sizeof(one),1)
fwrite(&one,sizeof(one),1,fp)
printf("\n\t\t\t 密码修改成功！")
break
}else{
printf("\n\t\t\t 两次密码输入不一致！")
}
}
}else{
printf("\n\t\t\t 密码输入错误！")
}
}
int zhuxiaozhanghao()
{
system("cls")
int zhuxiaoxitong
char sf
printf("你要注销的账号是%d",one.account)
printf("你是否要对此账号进行注销?\n\n\t\t请您选择:注销(Y)or不注销(N)：")
fflush(stdin)
scanf("%c",&sf)
if(sf=='y'||sf=='Y')
{
printf("正在为您注销!\n",one.account)
zhuxiaoxitong=1
}else{
printf("不注销系统!\n",one.account)
}
return zhuxiaoxitong
}
void service()
{
while(1){
system("cls")
printf("\n\n\n\t\t\t\t\t\t现在是服务系统,本系统有以下服务")
printf("\n\t\t\t\t\t\t[a] 查询余额\n")
printf("\n\t\t\t\t\t\t[b] 存款服务\n")
printf("\n\t\t\t\t\t\t[c] 转账服务\n")
printf("\n\t\t\t\t\t\t[d] 取款服务\n")
printf("\n\t\t\t\t\t\t[e] 修改密码\n")
printf("\n\t\t\t\t\t\t[f] 注销\n")
printf("\n\t\t\t\t\t\t[g] 退出系统\n")
char e
printf("\n\t\t\t\t\t\t您要选择的服务是:")
fflush(stdin)
scanf("%c",&e)
switch(e)
{ case'A':
case'a': searchmoney() break
case'B':
case'b': savemoney() break
case'C':
case'c': transfermoney() break
case'D':
case'd': withdrawalmoney() break
case'E':
case'e': xiugai() break
case'F':
case'f': {int zhuxiaoxitong=zhuxiaozhanghao(){if(zhuxiaoxitong==1) return}break}
case'G':
case'g': quite()break
}
printf("\n\n\n\t\t\t\t按任意键继续......\n")
getch()
}
}
void login()
{
fp=fopen("atm.txt","rb+")
if(fp==NULL)
{
printf("\n\n\n\t\t\t\t文件打开失败!")
return
}
system("cls")
printf("\n\t\t\t\t\t\t现在执行的是登录函数的使用\n")
int zhanghao
printf("\n\t\t\t\t\t\t请输入账号:")
scanf("%d",&zhanghao)
int flag=0
while(fread(&one,sizeof(one),1,fp)==1)
{
if(zhanghao==one.account){
flag=1
break
}
}
char password2[7]
if(flag==1){
int h
for(h=0h<3h++){
printf("\n\t\t\t\t\t\t请输入密码:")
fflush(stdin)
inputpassword(password2)
if(strcmp(password2,one.password)==0)
{
printf("\n\t\t\t\t\t\t登陆成功!")
service()
break
}else{
printf("密码不正确！")
}
}
if(h==3){
printf("\n\t\t\t您的密码三次输入有误,返回")
}
}else{
printf("无此账号！")
}
fclose(fp)
}
void quite()
{
system("cls")
printf("\t\t\t现在执行的是退出函数的使用\n")
exit(0)
}
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