JAVA用户怎么登录图形用户界面程序？

制作一个类似于QQ登陆的界面，以下数据库部分，你可以自己修该下，默认为Access；

import java.awt.*

import javax.swing.*

import java.awt.event.*

import java.sql.*

class JieMian extends JFrame；

{

JFrame f

JLabel lb1

JLabel lb2

JTextField tf

JPasswordField pwd

JButton b1

JButton b2

JPanel p1

JPanel p2

Connection con

Statement stmt

String use

char passw[]=new char[10]

ResultSet rs

String k1,k2

public void init()

f=new JFrame("登陆界面")

init()

b1.addActionListener(new ActionListener()

{

public void actionPerformed(ActionEvent ei)

{

try

{

Class.forName("sun.jdbc.odbc.JdbcOdbcDriver")

con=DriverManager.getConnection("jdbc:odbc:dat")

stmt=con.createStatement()

use=tf.getText()

passw=pwd.getPassword()

String passww=new String(passw)

rs=stmt.executeQuery("select * from user where 用户名='"+use+"' and  密码='"+passww+"'")

while(rs.next())

{

System.out.println(k1=rs.getString("用户名"))

System.out.println(k2=rs.getString("密码"))

}

if(k1.equals(use)&&(k2.equals(passww)))

{

JOptionPane.showMessageDialog(null,"用户登陆成功")//登陆成功

}

else

{

JOptionPane.showMessageDialog(null,"请检查用户信息，登陆失戚手败")//登侍扮录失败

}

rs.close()

stmt.close()

con.close()

}

catch (Exception ey){JOptionPane.showMessageDialog(null,"请检查用户信息，高谈嫌登陆失败")}

}

})

f.setLayout(new GridLayout(2,1,10,5))

f.setVisible(true)

f.setSize(210,150)

f.setLocation(550,300)

f.setResizable(false)

f.setDefaultCloseOperation(EXIT_ON_CLOSE)

b2.addActionListener(new ActionListener(){//58

public void actionPerformed(ActionEvent e){

f.setVisible(false)

}

})

}

}

public class DengLu

{

public static void main(String[] args)

{

new JieMian()

}

}。

package test\x0d\x0aimport java.util.Scanner\x0d\x0apublic class TestLogin {\x0d\x0aprivate static final String USERNAME = "Tom"/兄滑侍/此处定义用让旁户名\x0d\x0aprivate static final String PASSWORD = "123"//定义密码\x0d\x0apublic static void main(String[] args) {\x0d\x0aScanner sc = new Scanner(System.in)\x0d\x0aSystem.out.print("请输入您的用户名:")\x0d\x0aString username_in = sc.next()\x0d\x0aSystem.out.print("请输入您的密码:")\x0d\x0aString password_in = sc.next()\x0d\x0aif(username_in.equals(USERNAME) &&password_in.equals(PASSWORD)){\x0d\x0aSystem.out.println("登录成功")\x0d\x0a}else{\x0d\x0aSystem.out.println("用户名或羡吵密码错误")\x0d\x0a}\x0d\x0a}\x0d\x0a} \x0d\x0a这是从控制台输入的最简单的方法。

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