
%已拦脊知矩阵:A
%迭代步数:M
%求得的矩阵特征值:l
A = hess(A)
for i=1:M
N = size(A)
n = N(1,1)
u = A(n,n)
[q,r]=qr(A-u*eye(n,n))
A = r*q+u*eye(n,n)
l = diag(A)
end
------------------------------------
A=[0 5 0 0 0 01 0 4 0 0 00 1 0 3 0 00 0 1 0 2 00 0 0 1 0 10 0 0 0 1 0]
A =
0 5 0 0 0 0
1 0 4 0 0 0
0 1 0 3 0 0
0 0 1 0 2 0
0 0 0 1 0 1
0 0 0 0 1 0
>>rqrtz(A,50)
ans =
-3.2030
3.2030
-1.8837
1.8837
-0.6167
0.6167
>>eig(A)
ans =
-3.3243
3.3243
-1.8892
-0.6167
1.8892
0.6167
设特征值矩绝顷阵为V,你只要构造出一个随机的单位慎帆正宽宏雹交矩阵U,则 UVU'即为满足条件的矩阵: V = diag([1 2 3])U = orth(rand(3))A = U*V*U'欢迎分享,转载请注明来源:内存溢出
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