iOS非金额两位小数转化为大写中文

最近APP中出现该需求，所以自己开发了一下相关方法，具体代码如下，按需自取。

-(NSString *)changetochinese:(NSString *)numstr
{
    double numberals=[numstr doubleValue];
    NSArray *numberchar = @[@"零",@"壹",@"贰",@"叁",@"肆",@"伍",@"陆",@"柒",@"捌",@"玖"];
    NSArray *inunitchar = @[@"",@"拾",@"佰",@"仟"];
    NSArray *unitname = @[@"",@"万",@"亿",@"万亿"];
    //总额乘以100转换成字符串（去除小数值）
    NSString *valstr=[NSString stringWithFormat:@"%.2f",numberals];
    NSString *prefix;
    NSString *suffix;
    if (valstr.length<=2) {
        prefix=@"零点";
        if (valstr.length==0) {
            suffix=@"零零";
        }
        else if (valstr.length==1)
        {
            suffix=[NSString stringWithFormat:@"%@",[numberchar objectAtIndex:[valstr intValue]]];
        }
        else
        {
            NSString *head=[valstr substringToIndex:1];
            NSString *foot=[valstr substringFromIndex:1];
            suffix=[NSString stringWithFormat:@"%@%@",[numberchar objectAtIndex:[head intValue]],[numberchar objectAtIndex:[foot intValue]]];
        }
    }
    else
    {
        prefix=@"";
        suffix=@"";
        int flag=valstr.length-2;
        NSString *head=[valstr substringToIndex:flag-1];
        NSString *foot=[valstr substringFromIndex:flag];
        if (head.length>13) {
            return@"数值太大（最大支持13位整数），无法处理";
        }
        //处理整数部分
        NSMutableArray *ch=[[NSMutableArray alloc]init];
        for (int i = 0; i < head.length; i++) {
            NSString * str=[NSString stringWithFormat:@"%x",[head characterAtIndex:i]-'0'];
            [ch addObject:str];
        }
        int zeronum=0;
        
        for (int i=0; i