
data Zone = Zone { zID :: Int -- this zone's ID,zOwnerID :: Int -- the player who owns this zone (-1 otherwise),zPodsP0 :: Int -- player 0's PODs on this zone,zPodsP1 :: Int -- player 1's PODs on this zone,zPodsP2 :: Int -- player 2's PODs on this zone (always 0 for a two player game),zPodsP3 :: Int -- player 3's PODs on this zone (always 0 for a two or three player game) } deriving Show 从getline读取的[String]创建记录的短路是什么?
zones <- replicateM zoneCount $fmap (mkZone . words) getline
这是迄今为止我能做的最好的事情.
{-# LANGUAGE namedFIEldPuns #-}mkZone :: [String] -> ZonemkZone xs = Zone {zID,zOwnerID,zPodsP0,zPodsP1,zPodsP2,zPodsP3} where [zID,zPodsP3] = map read xs 在编写bot programmings编码时我会使用这种模式,如果有更好的方法可以做到这一点会很好.
解决方法RecordWildCards删除了一半的样板. {-# LANGUAGE RecorDWildCards #-}mkZone :: [String] -> ZonemkZone xs = Zone {..} where [zID,zPodsP3] = map read xs 总结 以上是内存溢出为你收集整理的haskell – 创建记录表单列表的最短方法是什么?全部内容,希望文章能够帮你解决haskell – 创建记录表单列表的最短方法是什么?所遇到的程序开发问题。
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