![[Swift Weekly Contest 108]LeetCode931. 下降路径最小和 | Minimum Falling Path Sum,第1张 [Swift Weekly Contest 108]LeetCode931. 下降路径最小和 | Minimum Falling Path Sum,第1张](/aiimages/%5BSwift+Weekly+Contest+108%5DLeetCode931.+%E4%B8%8B%E9%99%8D%E8%B7%AF%E5%BE%84%E6%9C%80%E5%B0%8F%E5%92%8C+%7C+Minimum+Falling+Path+Sum.png)
Given a square array of integers A,we want the minimum sum of a falling path through A.
A falling path starts at any element in the first row,and chooses one element from each row. The next row‘s choice must be in a column that is different from the prevIoUs row‘s column by at most one.
Example 1:
input: [[1,2,3],[4,5,6],[7,8,9]]Output: 12 Explanation: The possible falling paths are: [1,4,7],[1,8],9] [2,[2,9],6,9] [3,[3,9] The falling path with the smallest sum is [1,7],so the answer is 12.
Note:
1 <= A.length == A[0].length <= 100 -100 <= A[i][j] <= 100 给定一个方形整数数组 A,我们想要得到通过 A 的下降路径的最小和。
下降路径可以从第一行中的任何元素开始,并从每一行中选择一个元素。在下一行选择的元素和当前行所选元素最多相隔一列。
示例:
输入:[[1,9]]输出:12解释:可能的下降路径有:
[1,9] 和最小的下降路径是 [1,7],所以答案是 12。
提示:
1 <= A.length == A[0].length <= 100 -100 <= A[i][j] <= 100 196ms
1 class Solution { 2 func minFallingPathSum(_ A: [[Int]]) -> Int { 3 let m:Int = A[0].count 4 var dp:[Int] = A[0] 5 for j in 0..<(A.count - 1) 6 { 7 var row:[Int] = A[j] 8 var ndp:[Int] = [Int](repeating: Int.max / 2,count: m) 9 for i in 0..<m10 {11 for k in -1...112 {13 if i+k >= 0 && i+k < m14 {15 ndp[i + k] = min(ndp[i + k],dp[i] + A[j + 1][i + k])16 }17 }18 }19 dp = ndp20 }21 var ret:Int = Int.max22 for v in dp23 {24 ret = min(ret,v)25 }26 return ret27 }28 }总结
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