在flutter上测试shared_preferences

概述我正在写一个颤动的应用程序,我在编写测试时遇到了这个问题.该方法应该将数据写入TextFields并点击一个按钮,将该数据保存在SharedPrefs中： testWidgets('Click on login saves the credentials', (WidgetTester tester) async { await tester.pumpWidget(MyApp 我正在写一个颤动的应用程序,我在编写测试时遇到了这个问题.该方法应该将数据写入TextFIElds并点击一个按钮,将该数据保存在SharedPrefs中：

testWidgets('Click on login saves the credentials',(WidgetTester tester) async {    await tester.pumpWidget(MyApp());    await tester.enterText(find.byKey(Key('phoneinput')),'test');    await tester.enterText(find.byKey(Key('passwordinput')),'test');    await tester.tap(find.byIcon(Icons.lock));    SharedPreferences prefs = await SharedPreferences.getInstance();    expect(prefs.getString('phone'),'test');    expect(prefs.getString('password'),'test');  });

此测试将无法使用此错误获取SharedPreferences实例：

The following TimeoutException was thrown running a test:TimeoutException after 0:00:03.500000: The test exceeded the timeout. It may have hung.ConsIDer using "addTime" to increase the timeout before expensive operations.

更新：似乎问题实际上不是超时,因为即使60秒,测试也无法解析SharedPreferences实例.

解决方法 你需要从shared_preferences模拟getAll(参考： https://pub.dartlang.org/packages/shared_preferences)

这是示例代码：

import 'package:shared_preferences/shared_preferences.dart';import 'package:Flutter/services.dart'; // <-- needed for `MethodChannel`voID main() {  setUpAll(() {    const MethodChannel('plugins.Flutter.io/shared_preferences')        .setMockMethodCallHandler((MethodCall methodCall) async {      if (methodCall.method == 'getAll') {        return <String,dynamic>{}; // set initial values here if desired      }      return null;    });  });  testWidgets('Click on login saves the credentials',(WidgetTester tester) async {    await tester.pumpWidget(MyApp());    await tester.enterText(find.byKey(Key('phoneinput')),'test');  });}

原始答案：

testWidgets('Click on login saves the credentials',(WidgetTester tester) async {      final automatedTestWidgetsFlutterBinding binding = tester.binding;      binding.addTime(const Duration(seconds: 10)); // or longer if needed    await tester.pumpWidget(MyApp());    await tester.enterText(find.byKey(Key('phoneinput')),'test');  });

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