
select * from EMPLOYEE having EMP_ID in (select EMP_ID from ASSET,ASSET_REPORT where ASSET.AST_ID=ASSET_REPORT.AST_ID and getDate()>REP_DATE and AST_NAME='notebook') by DEP_NAME asc
简单解释下,(...)里的是获得满足是笔记本、且已过期的员工ID,在外面一层是获得这些ID属于的员工信息,并按部门编号排序
6、SELECT E#,COUNT(C#) AS NUM,SUM(SALARY) AS SUM_SALARY
FROM WORKS GROUP BY E#;
7、
SELECT X.E# FROM WORKS X WHERE NOT EXISTS
(SELECT * FROM WORKS Y WHERE E#=‘E6’AND NOT EXISTS
(SELECT * FROM WORKS Z WHERE Z.E#=X.E# AND Z.C#=Y.C#));
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