
- 选择两个素数p和q ,计算n=p*q和欧拉函数φ(n)=(p-1)(q-1),选择整数e,使gcd(φ(n), e)=1(即φ(n)和e是互素),1
- 计算e的逆元d=e-1mod φ(n)(即ed = 1 mod φ(n))
- 得到公钥Kpub={e, n},私钥Kpri={d, n}(公开公钥Kpub ,保密私钥Kpri )
- 加密(使用公钥Kpub):对于明文m
- 解密(使用私钥Kpri):对于密文c,明文m=cd mod n
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#includeusing namespace std; // 最大公因数 int maxCommonDivisor(int a, int b) { int temp = a; if (a < b) { a = b; b = temp; } while(a % b) { temp = b; b = a % b; a = temp; } return b; } // 最小公倍数 int leastCommonMultiple(int a, int b) { int macDivisor = maxCommonDivisor(a, b); return a / macDivisor * b; } // 计算 input ^ rate mod y int multiMod(int input, int rate, int y) { int start = 1; int arr[100]; arr[0] = 1; arr[1] = input; int step = 1; int result = 1; while(rate) { if (step == 1) { arr[step] = input; } else { arr[step] = arr[step - 1] * arr[step - 1]; arr[step] %= y; } if(rate&1) { result *= arr[step]; result %= y; } step ++; rate = rate >> 1; } return result; } int main() { int input; int p, q; int N, L, E, D; while(cin >> p >> q >> input >> E) { N = p * q; //最小公倍数 L = leastCommonMultiple(p - 1, q - 1); //E * D mod L = 1 int X = 1; while((X * L + 1) % E) { X ++; } D = (X * L + 1) / E; cout<<"N = " << N << " L = " << L << " E = " << E << " D = " << D << " X = " << X < 欢迎分享,转载请注明来源:内存溢出
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