【无标题】C++类型兼容规则_C

题目描述：根据main函数的内容倒推所涉及的几个类之间的关系，并完成这些的类的设计：

int main(){ Base1 b1; Base2 b2; Derived1 d1; Derived2 d2; Base1 *bp; bp=&b2; bp->doSomething(); //(1) cout< bp=&d1; bp->doSomething(); //(2) cout< bp=&d2; bp->doSomething(); //(3) cout< Base2 &br=d1; br.doSomething(); //(4) cout< d1.doSomething(); //(5) cout< d2.doSomething(); //(6) return 0; } 输入描述：无

#include
using namespace std;

class Base1
{
public:
	Base1(){}
	void doSomething()
	{
		cout << "Hello Base1" << endl;
	}
};
class Base2 :public Base1
{
public:
	Base2(){}
	void doSomething()
	{
		cout << "Hello Base2" << endl;;
	}
};
class Derived1 :public Base2
{
public:
	Derived1()
	{
		//Base1::doSomething();
		//Base2::doSomething();
	}
	void doSomething()
	{
		Base1::doSomething();
		Base2::doSomething();
		cout << "Hi Derived1"<

 
   
  
  
 
 
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【无标题】C++类型兼容规则

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