字典值求和

请补充横线处的代码。dictMenu中存放了你的双人下午套餐（包括咖啡2份和点心2份）的价格，让Python帮忙计算并输出消费总额。‪‬‪‬‪‬‪‬‪‬‮‬‭‬‫‬‪‬‪‬‪‬‪‬‪‬‮‬‫‬‪‬‪‬‪‬‪‬‪‬‪‬‮‬‫‬‭‬‪‬‪‬‪‬‪‬‪‬‮‬‭‬‫‬‪‬‪‬‪‬‪‬‪‬‮‬‫‬‭‬‪‬‪‬‪‬‪‬‪‬‮‬‫‬‪‬

dictMenu = {'卡布奇洛':32,'摩卡':30,'抹茶蛋糕':28,'布朗尼':26}
___①_  _ 
for i in ____②____:
    sum +=  i
print(sum)

dictMenu = {'卡布奇洛':32,'摩卡':30,'抹茶蛋糕':28,'布朗尼':26}
sum=0
dq=dictMenu.values()
for i in dq:
    sum +=  i
print(sum)

再举个例子：

def union_dict(*objs):

    _keys = set(sum([obj.keys() for obj in objs],[]))

    _total = {}

for _key in _keys:

    _total[_key] = sum([obj.get(_key,0) for obj in objs])

    return _total

obj1 = {'a':1,'b':2,'c':3}

obj2 = {'a':1,'b':3,'d':4}

print union_dict(obj1,obj2)

输出

{'a': 2, 'c': 3, 'b': 5, 'd': 4}