
总结三个坐标相关公式
因为需要用到三角函数,导入math库
import math
两个坐标计算距离的函数
def distance(Alongitude, Alatitude, Blongitude, Blatitude):
AEarth = 6378137.0
DEG_TO_RAD = 1.7453292519943e-2
RAD_to_DEG = 57.295779513082
startLat = Alatitude * DEG_TO_RAD
endLat = Blatitude * DEG_TO_RAD
dLat = (Blatitude - Alatitude) * DEG_TO_RAD
dLon = (Blongitude - Alongitude) * DEG_TO_RAD
a = math.sin(dLat / 2) * (math.sin(dLat / 2)) + math.sin(dLon / 2) * math.sin(dLon / 2) * math.cos(
startLat) * math.cos(endLat)
c = 2 * math.asin(min(1.0, math.sqrt(a)))
return AEarth * c
两坐标计算角度的函数
def degree(Alongitude, Alatitude, Blongitude, Blatitude):
radLatA = math.radians(Alatitude)
radLonA = math.radians(Alongitude)
radLatB = math.radians(Blatitude)
radLonB = math.radians(Blongitude)
dLon = radLonB - radLonA
y = math.sin(dLon) * math.cos(radLatB)
x = math.cos(radLatA) * math.sin(radLatB) - math.sin(radLatA) * math.cos(radLatB) * math.cos(dLon)
brng = math.degrees(math.atan2(y, x))
brng = (brng + 360) % 360
return brng
给定第一点经纬度、航向角和距离,计算第二点坐标函数
def CalculateCoordinates(lon, lat, brng, dist):
lat1 = lat * math.pi / 180
lon1 = lon * math.pi / 180
brg = brng * math.pi / 180
# 扁率
flat = 298.257223563
# 地球 半长轴
a = 6378137.0
# 地球 半短轴
b = 6356752.314245
f = 1 / flat
sb = math.sin(brg)
cb = math.cos(brg)
tu1 = (1 - f) * math.tan(lat1)
cu1 = 1 / math.sqrt((1 + tu1 * tu1))
su1 = tu1 * cu1
s2 = math.atan2(tu1, cb)
sa = cu1 * sb
csa = 1 - sa * sa
us = csa * (a * a - b * b) / (b * b)
A = 1 + us / 16384 * (4096 + us * (-768 + us * (320 - 175 * us)))
B = us / 1024 * (256 + us * (-128 + us * (74 - 47 * us)))
s1 = dist / (b * A)
s1p = 2 * math.pi
cs1m = 0.0
ss1 = 0.0
cs1 = 0.0
ds1 = 0.0
#
while abs(s1 - s1p) > 1e-12:
cs1m = math.cos(2 * s2 + s1)
ss1 = math.sin(s1)
cs1 = math.cos(s1)
ds1 = B * ss1 * (cs1m + B / 4 * (cs1 * (-1 + 2 * cs1m * cs1m) - B / 6 * cs1m * (-3 + 4 * ss1 * ss1) * (-3 + 4 * cs1m * cs1m)))
s1p = s1
s1 = dist / (b * A) + ds1
t = su1 * ss1 - cu1 * cs1 * cb
lat2 = math.atan2(su1 * cs1 + cu1 * ss1 * cb, (1 - f) * math.sqrt(sa * sa + t * t))
l2 = math.atan2(ss1 * sb, cu1 * cs1 - su1 * ss1 * cb)
c = f / 16 * csa * (4 + f * (4 - 3 * csa))
l = l2 - (1 - c) * f * sa * (s1 + c * ss1 * (cs1m + c * cs1 * (-1 + 2 * cs1m * cs1m)))
lon2 = lon1 + l
Longitude = lon2 * 180 / math.pi
Latitude = lat2 * 180 / math.pi
return Longitude, Latitude
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