c:如何在构造函数中初始化std :: pair的成员

c:如何在构造函数中初始化std :: pair的成员,第1张

概述我有以下课程: typedef std::pair<boost::asio::ip::tcp::socket, boost::asio::ip::tcp::socket> socket_pair;class ConnectionPair {private: socket_pair _sockPair;public: ConnectionPair(boost::asio:: 我有以下课程:

typedef std::pair<boost::asio::ip::tcp::socket,boost::asio::ip::tcp::socket>  socket_pair;class ConnectionPair {private:    socket_pair _sockPair;public:    ConnectionPair(boost::asio::io_service &ios);}

如何在构造函数初始化对中的套接字?以下内容无法编译:

ConnectionPair::ConnectionPair(asio::io_service &ios):    _ios(ios),_sockPair(asio::ip::tcp::socket(ios),asio::ip::tcp::socket(ios)){}

编辑:这是编译器错误.请享用:

/boost_1_47_0/boost/asio/basic_io_object.hpp: In copy constructor ‘boost::asio::basic_socket<boost::asio::ip::tcp,boost::asio::stream_socket_service<boost::asio::ip::tcp> >::basic_socket(const boost::asio::basic_socket<boost::asio::ip::tcp,boost::asio::stream_socket_service<boost::asio::ip::tcp> >&)’:/boost_1_47_0/boost/asio/basic_socket.hpp:43:1:   instantiated from ‘std::pair<_T1,_T2>::pair(const _T1&,const _T2&) [with _T1 = boost::asio::basic_stream_socket<boost::asio::ip::tcp>,_T2 = boost::asio::basic_stream_socket<boost::asio::ip::tcp>]’/devel/msm1/connection.cpp:8:67:   instantiated from here/boost_1_47_0/boost/asio/basic_io_object.hpp:163:3: error: ‘boost::asio::basic_io_object<IoObjectService>::basic_io_object(const boost::asio::basic_io_object<IoObjectService>&) [with IoObjectService = boost::asio::stream_socket_service<boost::asio::ip::tcp>,boost::asio::basic_io_object<IoObjectService> = boost::asio::basic_io_object<boost::asio::stream_socket_service<boost::asio::ip::tcp> >]’ is private/boost_1_47_0/boost/asio/basic_socket.hpp:43:1: error: within this contextIn file included from /boost_1_47_0/boost/asio.hpp:30:0,
解决方法 如果类型是可复制构造的,那么您的代码就可以工作了.我猜(并且只是猜测,因为你没有指定编译器错误)套接字不是可复制构造的.由于std :: pair不允许就地工厂,你必须使你的对成为一对boost :: optional并使用就地工厂.有关详细信息,请参见 the boost documentation. 总结

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