
如何在plone.app.testing中为我的功能测试添加Members文件夹,以便在真实站点中找到它?
在我正在测试的产品安装步骤中设置了成员区域创建标志.
membership.memberareaCreationFlag = 1 我需要让这个测试工作:
class TestMemberFolder(unittest.TestCase): layer = MY_FUNCTIONAL_TESTING def setUp(self): portal = self.portal = self.layer['portal'] def test_members_folder(self): membership = getToolByname(self.portal,'portal_membership') membership.addMember("basicuser","secret",["Member"],[]) transaction.commit() login(self.portal,"basicuser") # This works just fine,because it was set by my product self.assertEquals(membership.memberareaCreationFlag,1,"memberareaCreationFlag must be 1 when it is enabled") members_folder = membership.getMembersFolder() # But this fails self.assertIsNotNone(members_folder) # Also we should have the user folder here self.assertTrue(members_folder.hasObject('basicuser'))我特别需要会员文件夹功能.只是测试用户拥有的文件夹不会削减它.
此外,我尝试使用acl_users.userFolderAddUser创建新用户,但这无助于更好.
memberareaCreationFlag在现场Plone网站上运行得很好.
最佳答案我终于弄明白了.首先,membership.memberareaCreationFlag = 1不足以启用成员文件夹.
必须在plone.app.controlpanel.security中使用SecurityControlPanelAdapter启用它
from plone.app.controlpanel.security import ISecuritySchema# Fetch the adaptersecurity_adapter = ISecuritySchema(portal)security_adapter.set_enable_user_folders(True)此外,功能测试夹具不会自动创建成员文件夹,但可以在夹具类中手动安装
class YourPloneFixture(PlonesandBoxLayer): defaultBases = (PLONE_FIXTURE,) def setUpZope(self,app,configurationContext): # required by Products.Cmfplone:plone-content z2.installProduct(app,'Products.PythonScripts') def setUpPlonesite(self,portal): # Installs all the Plone stuff. Workflows etc. self.applyProfile(portal,'Products.Cmfplone:plone') # Install portal content. Including the Members folder! self.applyProfile(portal,'Products.Cmfplone:plone-content')最后,因为会员文件夹是通过用户登录创建的,但plone.app.testing中的登录帮助程序函数似乎太低了.使用zope.testbrowser登录似乎可以解决问题
browser = browser(self.layer['app'])browser.open(self.portal.absolute_url() + '/login_form')browser.getControl(name='__ac_name').value = TEST_USER_namebrowser.getControl(name='__ac_password').value = TEST_USER_PASSWORbrowser.getControl(name='submit').click()唷. 总结
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