
{
switch (a)
{
case 0:
return "ling"
break
case 1:
return "yi"
break
case 2:
return "er"
break
case 3:
return "san"
break
case 4:
return "si"
break
case 5:
return "wu"
break
case 6:
return "liu"
break
case 7:
return "qi"
break
case 8:
return "ba"
break
case 9:
return "jiu"
break
}
}
int main()
{
int i
printf("请输入一个数字:-9999-9999\n")
scanf("%d", &i)
string ret = ""
if (i < 0)
ret = ret + "fu "
i = -i
int a = 0
if (i >= 1000)
{
a = i / 1000
ret = ret + inttochar(a) + " qian "
i = i - 1000 * a
a = i / 100
if(a != 0)
ret = ret + inttochar(a) + " bai "
i = i - 100 * a
a = i / 10
if(a != 0)
ret = ret + inttochar(a) + " shi "
i = i - 10 * a
a = i
if(a != 0)
ret = ret + inttochar(a)
}
else if (i < 1000 && i >= 100)
{
a = i / 100
ret = ret + inttochar(a) + " bai "
i = i - 100 * a
a = i / 10
if (a != 0)
ret = ret + inttochar(a) + " shi "
i = i - 10 * a
a = i
if (a != 0)
ret = ret + inttochar(a)
}
else if (i < 100 && i >= 10)
{
a = i / 10
if (a != 0)
ret = ret + inttochar(a) + " shi "
i = i - 10 * a
a = i
if (a != 0)
ret = ret + inttochar(a)
}
else if (i < 10 && i >= 0)
{
ret = ret + inttochar(i)
}
printf(ret.c_str())
return 0
}
真尼玛哔了狗了,这破玩意写起来真费事
//这段程序错误太多,而且代码风格太乱;
//不过估计您是个初学者,就帮你的程序按你思路修改了
//运行结果如下:
模仿拼音输入法
请输入拼音wo
wo
0.挝 1.莴 2.涡 3.窝 4.蜗 5.倭 6.踒 7.喔 8.我 9.肟 10.沃 11.卧 12.偓 13.握 14.幄
15.渥 16.龌 17.涴 18.硪 19.斡 请输入对应的序号选字:2
涡
//修改后程序如下,希望对你有用!
#include<stdio.h>
#include<string.h>
int main() //是int还是void,根据编译器,我用的是CodeBlocks需要用int
{
char wo[]= {"wo"}
char wo_ch[]= {"挝莴涡窝蜗倭踒喔我肟沃卧偓握幄渥龌涴硪斡"}
printf("%d:%s\n", strlen(wo_ch), wo_ch)
//char str_input[3]
unsigned int i=0,str_ch_len=strlen(wo_ch)
printf("模仿拼音输入法\n")
printf("请输入拼音wo\n")
//scanf("%s",str_input)
char str_input[3]
gets(str_input)//输入拼音
//if(str_input==wo)//修改如下(字符串是不能直接比较的!)
if (0==strcmp(str_input,wo))
{
for(i=0 i<str_ch_len i+=2)
//printf("%d.%c "i,wo_ch[i]) //修改如下(双引号之后应该有,号)
printf("%d.%c%c ",i/2,wo_ch[i],wo_ch[i+1])
last:
printf("请输入对应的序号选字:")
//scanf("%d" &i) //修改如下
unsigned int n
scanf("%u", &n)
if (2*n>str_ch_len)
{
printf("你要选的字符不存在\n")
goto last
}
else
{
printf("%c%c",wo_ch[2*n],wo_ch[2*n+1])
}
}
else
{
printf("对不起,没有找到该拼音的字库\n")
}
return 0//如果主函数是void,删除此行!
}
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